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lara [203]
3 years ago
9

45 grams of ammonia, NH3, in 0.75 L of solution.

Chemistry
1 answer:
GrogVix [38]3 years ago
4 0
2.3 moles of sodium chloride in 0.45 liters of solution . necessarile correct ... 0.025 L. (1.3 SF). 45 grams of ammonia in 0.75 L of solution. 45g x 1 mol = 2. demol ... anol x 1,50 = 3 mol NaOH x 40,019 = 120g Naolt.
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17 Two substances in a mixture differ in density and particle size. These properties can be used to(1) separate the substances
belka [17]
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Read 2 more answers
What do the conclusions tell about the experiment?
Blababa [14]

Answer:

Option C

Explanation:

When you perform a experiment to test your hypothesis (your educated guess on what you think will happen) you complete trials to find data that is reliable and valid so you are only getting the best possible results. After you complete the experiment you write your conclusion which is when you take the data and you say if the data supported your hypothesis, if you did guess correctly at the beginning of the experiment. Which means the answer is option C "the conclusions tell why the data support or reject the hypothesis."

Hope this helps.

3 0
2 years ago
635 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at standard pressure (STP)?
Sveta_85 [38]

The new volume at standard temperature and pressure is 5.08 L.

Explanation:

As per the kinetic theory of gases, the volume occupied by gas molecules will be inversely proportional to the pressure of the gas molecules. This is termed as Boyle's law.

So, pressure∝\frac{1}{volume}

Thus, if two pressure and two volumes are given then,

P_{1} V_{1} = P_{2} V_{2}\\

Now, we known the values of P₁ = 8 atm, V₁ = 635 mL, P₂ = 1 atm and V₂ we have to determine. We are considering P₂ = 1 atm, because we have to determine V₂ at standard temperature and pressure. And standard pressure is 1 atm.

8*635*10^{-3}  = 1 *V{2} \\\\V_{2} = \frac{8*635*10^{-3} }{1} =   5.08 L

Thus, the new volume at standard temperature and pressure is 5.08 L.

5 0
3 years ago
An HCl solution has a concentration of 9.8 x 10-5 M. What is the pH of this solution?
Inessa05 [86]
HCl = H⁺ + Cl⁻

c(HCl)=9.8*10⁻⁵ mol/l

pH=-lg[H⁺]

[H⁺]=c(HCl)

pH=-lg{c(HCl)}

pH=-lg{9.8*10⁻⁵}=4.009

pH=4.009
7 0
3 years ago
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