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Lana71 [14]
3 years ago
8

How many milliliters of 0.111 m hclo4 solution are needed to neutralize 50.00 ml of 0.0789 m naoh?

Chemistry
1 answer:
Lunna [17]3 years ago
3 0
HClO₄ is a strong acid and NaOH is a strong base. Therefore they completely dissociate in the solution.
NaOH + HClO₄ ---> NaClO₄ + H₂O
stoichiometry of acid to base is 1:1
amount of NaOH moles reacted - 0.0789 M / 1000 mL/L x 50.00 mL
                                                   = 0.00395 mol
Amount of HClO₄  moles reacted = 0.00395 mol
Molarity of HClO₄ is 0.111 M 
Volume of HClO₄ l containing 0.111 mol -  1 L
Therefore volume of HClO₄  containing 0.00395 mol- 1/0.111 x 0.00395 = 0.0356 L
Volume of HClO₄  - 35.6 mL  

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A sample of an unknown gas with a mass of 8.21 g has a volume of 4.8064 L when the temperature is 200oC and the pressure is 1.81
Pie

Answer:

The answer to your question is M = 36.49 g

Explanation:

Data

mass = 8.21 g

volume = 4.8064 L

Temperature = 200°C

Pressure = 1.816 atm

M = ?

Process

1.- Convert temperature to °K

°K = 273 + 200

°K = 473

2.- Calculate the number of moles

n = (PV)/RT

n = (1.816)(4.8064)/(0.082)(473)

n = 0.225

3.- Calculate the molar mass

            M --------------- 1 mol

           8.21 g ---------- 0.225 moles

M = (1 x 8.21)/0.225

M = 36.49 g

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3 years ago
Please help
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3 years ago
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dangina [55]

Answer:

Explanation:

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