How can noble gas electron configuration be achieved?

Chemistry

1 answer:

lina2011 [118]2 years ago

7 0

Answer:

A noble gas configuration of an atom consists of the elemental symbol of the last noble gas prior to that atom, followed by the configuration of the remaining electrons. So for sodium we make the substitution of (Ne) for the 1s22s22p6 part of the configuration. Sodium's noble gas configuration becomes (Ne) 3s1.

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A polar covalent bond will form between which two atoms?

Alex_Xolod [135]

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

Less than 0.4 then it is Non Polar Covalent

Between 0.4 and 1.7 then it is Polar Covalent

Greater than 1.7 then it is Ionic

For Be and F,

E.N of Fluorine = 3.98

E.N of Beryllium = 1.57

________

E.N Difference 2.41 (Ionic Bond)

For H and Cl,

E.N of Chorine = 3.16

E.N of Hydrogen = 2.20

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E.N Difference 0.96 (Polar Covalent Bond)

For Na and O,

E.N of Oxygen = 3.44

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For F and F,

E.N of Fluorine = 3.98

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E.N Difference 0.00 (Non-Polar Covalent Bond)

Result:

A polar covalent bond is formed between Hydrogen and Chlorine atoms.

5 0

3 years ago

Elements that have atoms with stable valence electron configurations in the ground state are found in

dsp73

Answer:

Group 18, also known as the Noble Gasses

Explanation:

Atoms strive for full stability by gaining or losing electrons to get 8 valence electrons in their valence shell, but Group 18 already has 8 electrons in their valence shell, and are therefore already stable in their ground state.

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3 years ago

Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t

Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

$(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)$