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wlad13 [49]
3 years ago
8

Why are ethics important when considering experiments??

Chemistry
2 answers:
Likurg_2 [28]3 years ago
7 0

The correct answer would be,

It is important that people are not harmed for the sake of science.  -apex

IRINA_888 [86]3 years ago
4 0
Having a standard is ethical practices is important when considering experiments because it promotes the goals of the research such as the truth and knowledge. This will stop researchers from falsifying data and minimizes error in research. Research generally requires a great deal of collaboration between scientists and having a code of ethics will allow researchers to trust one another and be accountable for their work. Also, researchers need to be held accountable to the public and this can help build public support for that particular research. Ethics will also promote social and moral values, such as human and animal rights.
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The standard enthapy of combustion of solid urea co(nh2)2 is -632kjmol-1 at 298k​
Setler79 [48]

Answer:

The standard enthalpy of combustion of solid urea ((CO(NH2)2) is -632 kJ mol-1 at 298 K and its standard molar entropy is 104.60 J K-1 mol-1

Explanation:

8 0
3 years ago
Check my answer?
rusak2 [61]
Yes that is correct because hypotheses should be testable meaning it can be proven wrong and it has to be reasonable meaning it should make sense. 
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3 years ago
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If you increase the temperature of a reaction, then the reaction rate will ...
DIA [1.3K]
The answer is B.Increase
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3 years ago
What discovery led J.J. Thomson to decide that atoms were not indivisible, but are actually composed of smaller parts?
Zarrin [17]
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7 0
3 years ago
Hello!
blondinia [14]

Answer:

[CO]=[Cl_2]=0.01436M

[COCl_2]=0.00064M

Explanation:

Hello there!

In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:

K=\frac{[CO][Cl_2]}{[COCl_2]}

Which can be written in terms of x, according to the ICE table:

0.32=\frac{x^2}{0.015M-x}

Thus, we solve for x to obtain that it has a value of 0.01436 M and therefore, the concentrations at equilibrium turn out to be:

[CO]=[Cl_2]=0.01436M

[COCl_2]=0.015M-0.01436M=0.00064M

Regards!

5 0
2 years ago
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