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wlad13 [49]
3 years ago
8

Why are ethics important when considering experiments??

Chemistry
2 answers:
Likurg_2 [28]3 years ago
7 0

The correct answer would be,

It is important that people are not harmed for the sake of science.  -apex

IRINA_888 [86]3 years ago
4 0
Having a standard is ethical practices is important when considering experiments because it promotes the goals of the research such as the truth and knowledge. This will stop researchers from falsifying data and minimizes error in research. Research generally requires a great deal of collaboration between scientists and having a code of ethics will allow researchers to trust one another and be accountable for their work. Also, researchers need to be held accountable to the public and this can help build public support for that particular research. Ethics will also promote social and moral values, such as human and animal rights.
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An iceberg has a volume of 8925 ft3. is the mass in kilograms of the iceberg?
Novay_Z [31]
In chem it usually would be but it depends on your units and the instructions
6 0
3 years ago
What’s the molar mass of Lead-208
Degger [83]
Lead is a basic metal and almost 11 isotopes of Lead are reported. The isotopes with greater natural abundance are as follow;

1) ²⁰⁸Pb with abundance 52.4 %

2) ²⁰⁶Pb with abundance 24.1 %

3) ²⁰⁷Pb with abundance 22.1 %

4) ²⁰⁴Pb with abundance 1.4 %

Molar mass of ²⁰⁸Pb:

Molar mass of any element is the total of number of protons, neutrons and electrons.
As, number of protons in Lead are 82 then in ²⁰⁸Pb isotope number of neutrons are...

# of Neutrons  =  M.mass - # of protons

# of Neutrons  =  208 - 82

# of Neutrons  =  126

Result:

Molecular Mass of Lead (²⁰⁸Pb) is 208 amu.

# of Protons in ²⁰⁸Pb  = 82

# of Neutrons in ²⁰⁸Pb = 126
7 0
3 years ago
Calculate the number of moles in 2.67 g of carbon trihydride
Scorpion4ik [409]

Answer:0.178 moles

Explanation: carbon trihydride seems to be an unusual name for the methyl group CH3–

ionic wt 15

moles = 2.67/15 = 0.178

8 0
2 years ago
Polonium- 210 , Po210 , decays to lead- 206 , Pb206 , by alpha emission according to the equation Po84210⟶Pb82206+He24 If the ha
elixir [45]

Answer:

0.269 g

Explanation:

Po_{210} ^{84}  ⟶  Pb_{206} ^{82}+  + He_{4} ^{2}

Data:

Half-life of  Po_{210} ^{84}  (T(1/2)) = 138.4 days

Mass of PoCl4 = 561 mg (0,561 g) and molecular weight of PoCl4 = 350. 79 g/mol  

Time = 338.8 days  

Isotopic masses  

Po_{210} ^{84} = 209.98 g/mol  

Pb_{206} ^{82} = 205.97 g/mol  

Concepts  

Avogadro’s number: This is the number of constituent particles that are contained in a mol of any substance. These constituted particles can be atoms, molecules or ions). Its value is 6.023*10^23.  

The radioactive decay law is  

N=Noe^(-λt)

Where:  

No = number of atoms in t=0

N = number of atoms in t=t (now) in this case t=338.8 days  

λ= radioactive decay constant  

The radioactive constant is related to the half-life by the next equation  

λ= \frac{ln 2}{t(1/2)}

so  

λ= \frac{ln2}{138.4 days}  =0,005008 days^(-1)

No (Atoms of  Po_{210} ^{84}  in t=0)

To get No we need to calculate the number of atoms of  Po_{210} ^{84}   in the initial sample. We have a sample of 0,561 g of PoCl4. If we get the number of moles of PoCl4 in the sample, this will be the number of moles of  Po_{210} ^{84}  in the initial sample.  

This is:

\frac{0,561 g of PoCl4}{350. 79 g of PoCl4 /mol} = 0,001599 mol of  PoCl4

This is the number of mol of  Po_{210} ^{84} in the initial sample.

To get the number of atoms in the initial sample we use the Avogadro’s number = 6.023*10^23  

0,001599 mol of  Po_{210} ^{84} * 6.023*10^23 atoms/ mol of  Po_{210} ^{84} = 9.632 *10^20 atoms of  Po_{210} ^{84}

Atoms after 338.8 days

We use the radioactive decay law to get this value  

N=Noe^(-λt)

N=9.632*10^20 e^(-0,005008 days^(-1) * 338.8 days) =1.765*10^20

This is the number of atoms of  Po_{210} ^{84} in the sample after 338.8 days has passed  

The number of atoms  Po_{210} ^{84} transformed is equal to the number of atoms of Pb_{206} ^{82}  produced.  

The number of atoms of Po_{210} ^{84} transformed is No - N  

9.632 *10^20 – 1.765 *10^20 = 7.866*10^20

So, 7.866*10^20 is the number of atoms of Pb_{206} ^{82} produced  

We can get the mass with the Avogadro’s number

(7.866*10^20 atoms of Pb_{206} ^{82} ) / ( 6.023*10^23 atoms of Pb_{206} ^{82} / mol of Pb_{206} ^{82} =  0.001306 moles of Pb_{206} ^{82}

This number of moles have a mass of:

(0,001306 moles of Pb_{206} ^{82} )* (205.97 g of Pb_{206} ^{82} /mol of Pb_{206} ^{82} ) = 0.269 g  

3 0
3 years ago
Which numbers are shown in the symbol for a radioactive nuclide?
xz_007 [3.2K]
It would be 6 because of the elements
3 0
3 years ago
Read 2 more answers
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