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arlik [135]
4 years ago
15

During the first 10 seconds of a rocket launch, the momentum of the rocket increased by 8000 kg*m/s. What was the impulse applie

d to the rocket during this time?
Physics
2 answers:
mrs_skeptik [129]4 years ago
5 0

Answer:

I = 8000 kg*m/s

Explanation:

drek231 [11]4 years ago
4 0

Answer:

I = 8000 kg*m/s

Explanation:

given,                                                      

time interval = 10 sec                                      

momentum of the rocket is increased by = 8000 kg*m/s

Impulse applied = ?                                              

Impulse is equal to the change in momentum of the object.

Impulse is defined as the change in momentum of the body due to the force acting on the body for an instant of time.

In the question change of momentum is given as  8000 kg*m/s

So, the impulse applied during the interval of time will be equal to

          I = 8000 kg*m/s

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The energy of a photon of light is __________ proportional to its frequency and __________ proportional to its wavelength.
icang [17]

Answer:

D) directly, inversely

Explanation:

The energy of a photon of light is directly proportional to its frequency and inversely proportional to its wavelength.

Frequency is the number of waves that passes through a point per unit of time.

Wavelength is the is the distance between successive crests or troughs on a wave.

 Mathematically, frequency is related to wavelength and velocity using;

             Energy   =  h x f

                      where h is the Planck's constant

                                  f is the frequency

         

                   Since c  = f ∧

where f is the frequency of the wave

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So;

                 f  = c/∧

  Therefore;

                E  = \frac{h c}{wavelength}

From the equation, we see an inverse relationship between E and wavelength and a direct one with frequency.

           

6 0
3 years ago
A ball is thrown horizontally from a platform so that the initial height of the ball is 6.0 m above the level ground below. The
solniwko [45]
We can first obtain time of flight from vertical fall
Initial velocity U=0, d = 6 m, a = 9.8 m/s² 
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6.0 = 0 + (1/2 × 9.80 t²) 
t = √(12/9.8)
 = 1.106 sec
Horizontal velocity = Vh = Dh/t
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The ball was thrown at a speed of 21.69 m/s
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4 years ago
Which one you think is easier
Gnoma [55]

The third option looks easier

3 0
3 years ago
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pogonyaev

Answer:

Explanation:

3.75 * 10^-7

=3.75 * 1/10^7

=3.75/10000000

=3/800000000

any base which has it's power negative do it's reciprocal then the power will be positive.

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Answer:

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Explanation:

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