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Naddik [55]
3 years ago
15

How would you calculate an object’s mechanical energy? a. Add its kinetic and potential energies. b. Multiply its kinetic and po

tential energies. c. Subtract its kinetic energy from its potential energy. d. Subtract its potential energy from its kinetic energy.
Physics
2 answers:
dalvyx [7]3 years ago
6 0
A. Add it's Kinetic and Potential energies
Ahat [919]3 years ago
6 0
We know that:
EM=Ek+Epg
So basically you just sum the kinetic plus the potential energy and that´s it. (a)
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Consider the points below. P(1, 0, 1), Q(−2, 1, 4), R(6, 2, 7) (a) Find a nonzero vector orthogonal to the plane through the poi
kozerog [31]

Answer:

a) (0, -33, 12)

b) area of the triangle : 17.55 units of area

Explanation:

<h2>a) </h2>

We know that the cross product of linearly independent vectors \vec{A} and \vec{B} gives us a nonzero, orthogonal to both, vector. So, if we can find two linearly independent vectors on the plane through the points P, Q, and R, we can use the cross product to obtain the answer to point a.

Luckily for us, we know that vectors \vec{A} = \vec{P}-\vec{Q} and \vec{B} = \vec{R} - \vec{Q} are living in the plane through the points P, Q, and R, and are linearly independent.

We know that they are linearly independent, cause to have one, and only one, plane through points P Q and R, this points must be linearly independent (as the dimension of a plane subspace is 3).

If they weren't linearly independent, we will obtain vector zero as the result of the cross product.

So, for our problem:

\vec{A} = \vec{P} - \vec{Q} \\\\\vec{A} = (1,0,1) - (-2,1,4)\\\\\vec{A} = (1 +2,0-1,1-4)\\\\\vec{A} = (3,-1,-3)

\vec{B} = \vec{R} - \vec{Q} \\\\\vec{B} = (6,2,7) - (-2,1,4)\\\\\vec{B} = (6 +2,2-1,7-4)\\\\\vec{B} = (8,1,3)

\vec{A} \times  \vec{B} = (A_y B_z - B_y A_z) \  \hat{i} - ( A_x B_z-B_xA_z) \ \hat{j} + (A_x B_y - B_x A_y ) \ \hat{k}

\vec{A} \times  \vec{B} = ( (-1) * 3 - 1 * (-3) ) \  \hat{i} - ( 3 * 3 - 8 * (-3)) \ \hat{j} + (3 * 1 - 8 * (-1) ) \ \hat{k}

\vec{A} \times  \vec{B} = ( - 3 + 3 ) \  \hat{i} - ( 9 + 24 ) \ \hat{j} + (3 + 8 ) \ \hat{k}

\vec{A} \times  \vec{B} = 0 \  \hat{i} - 33 \ \hat{j} + 12 \ \hat{k}

\vec{A} \times  \vec{B} =(0, -33, 12)

<h2>B)</h2>

We know that \vec{A} and \vec{B} are two sides of the triangle, and we also know that we can use the magnitude of the cross product to find the area of the triangle:

|\vec{A} \times  \vec{B} | = 2 * area_{triangle}

so:

\sqrt{(-33)^2 + (12)^2} = 2 * area_{triangle}

\sqrt{1233} = 2 * area_{triangle}

35.114= 2 * area_{triangle}

17.55 \ units \  of \ area =  area_{triangle}

5 0
3 years ago
A roster lays an egg on top of a barn,the wind is blowing west,which way does the egg roll?
pogonyaev
Hahahahhahaha A ROSTER NEVER LAYS THE EGGS IT IS THE HEN THAT LAYS THE EGGS.....ITS LIKE MEN GETTING PREGNANT LOL
7 0
3 years ago
Read 2 more answers
Calcular el volumen de un cubo 36 cm​
3241004551 [841]

Answer:

vol = 46,566 cm³

Explanation:

calcular el volumen de un cubo 36 cm​

find: volume

let side of a cube = 36 cm

vol = side ³

vol = 36 ³

vol = 46,566 cm³

8 0
3 years ago
A 2300 kg truck has put its front bumper against the rear bumper of a 2400 kg SUV to give it a push. With the engine at full pow
IrinaK [193]

Answer:

a) a_{max} = 3.8\,\frac{m}{s^{2}}, b) F = 9260\,N

Explanation:

a) The maximum possible acceleration that the truck can give to the SUV is:

a_{max} = \frac{18,000\,N}{2,400\,kg+2300\,kg}

a_{max} = 3.8\,\frac{m}{s^{2}}

b) The equation of equilibrium for the truck is:

18,000\,N - F = (2,300\,kg)\cdot (3.8\,\frac{m}{s^{2}})

The force of the SUV's bumper on the truck's bumper is:

F = 9260\,N

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PLEASE HELP PLEASE HELP ME PLEASE HELP ME ​
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Answer:24

Explanation:

7 0
2 years ago
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