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icang [17]
2 years ago
14

An arrow of mass 20 g is shot horizontally into a bale of hay, striking the hay with a velocity of 60 m/s. It penetrates a depth

of 40 cm before stopping. What is the average stopping force acting on the arrow
Physics
1 answer:
goblinko [34]2 years ago
5 0

From the question, The kinetic energy of the fired arrow is equal to the work done by the bale of hale in stopping the arrow.

We make use of the following formula

mv²/2 = F'd................... Equation 1

Where

  • m = mass of the arrow
  • v = velocity of the arrow
  • F' = average stopping force acting on the arrow
  • d = distance of penetration

Make F' the subject of the equation

F' = mv²/2d.................. Equation 2

From the question,

Given:

  • m = 20 g = 0.02 kg
  • v = 60 m/s
  • d = 40 cm = 0.4 m

Substitute these values into equation 2

  • F' = 0.02(60²)/(0.4×2)
  • F' = 72/0.8
  • F' = 90 N

Hence, The average stopping force acting on the arrow is 90 N

Learn more about average stooping force here: brainly.com/question/13370981

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A distance of d is covered with 53 mile/hr initially. Time taken to cover this distance t1 = d/53 hour Next distance of d is covered with x mile hours. Time taken to cover this distance t2 = d/x hours. We have average speed = 26.5 mile / hour          

                                         = Total distance traveled/ total time taken                  

                                         = \frac{2d}{\frac{d}{53}+\frac{d}{x}} = \frac{2}{\frac{1}{53}+\frac{1}{x} }  = \frac{106x}{x+53}

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When a pitcher throws a baseball, it reaches a top speed of 39 m/s. if the
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From the calculation, the acceleration of the body is 26m/s^2.

<h3>What is motion under gravity?</h3>

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Given that;

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