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3 years ago

How many atoms in 10.0 g of Ar?

Chemistry

1 answer:

NARA [144]3 years ago

6 0

Answer:

1.51 x 10^23 atoms of Ar

Explanation:

Start out with what you're given.

10.0 g of Ar/1 * 1 mol/39.948 g Ar * 6.022*10^23 atoms/1 mol

(It's easier if you write it out.)

You always want to start out w/ what you're given and continue your unit conversions from there. Since you started out with grams of Argon, you want grams of Argon on the bottom to cancel it out. Once you found the unit conversion: 1 mol/39.948 g Ar (molar mass of Ar), now it's time to convert to atoms. Since 1 mol is up on top, put 1 mol on the bottom. Considering you're looking for atoms, use Avagradro's number: 6.022*10^23.

Once simplified, you should get 1.51 x 10^23 atoms of Ar.

***I hope this helps! I also suggest using a mole map, if you're interested.***

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Write Huckel's rule below and determine how many electrons are required to make an aromatic ring with n = 0, 1, and 2.

lisov135 [29]

Answer: The number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

Explanation:

Huckel's rule is used to determine the aromaticity in a compound. The number of delocalized $\pi-$ electrons are calculated by using the equation:

$\text{Number of delocalized }\pi-\text{ electrons}=4n+2$

where,

n = 0 or any whole number

Calculating the value of electrons for n = 0

Putting values in above equation, we get:

$\text{Number of delocalized }\pi-\text{ electrons}=4(0)+2=2$

Calculating the value of electrons for n = 1

Putting values in above equation, we get:

$\text{Number of delocalized }\pi-\text{ electrons}=4(1)+2=6$

Calculating the value of electrons for n = 2

Putting values in above equation, we get:

$\text{Number of delocalized }\pi-\text{ electrons}=4(2)+2=10$

Hence, the number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

4 0

3 years ago

A 3.301 mass % aqueous solution of potassium hydroxide has a density of 1.05 g/mL. Calculate the molality of the solution. Give

8_murik_8 [283]

Answer: The molality of potassium hydroxide solution is 0.608 m

Explanation:

We are given:

3.301 mass % of potassium hydroxide solution.

This means that 3.301 grams of potassium hydroxide is present in 100 grams of solution

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Mass of solvent = (100 - 3.301) g = 96.699 g

To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams})}$

Where,

$m_{solute}$ = Given mass of solute (KOH) = 3.301 g

$M_{solute}$ = Molar mass of solute (KOH) = 56.1 g/mol

$W_{solvent}$ = Mass of solvent = 96.699 g

Putting values in above equation, we get:

$\text{Molality of KOH}=\frac{3.301\times 1000}{56.1\times 96.699}\\\\\text{Molality of KOH}=0.608m$

Hence, the molality of potassium hydroxide solution is 0.608 m

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3 years ago

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docker41 [41]

Answer:

Amplitude does not effect the wavelength in linear system.

Explanation:

Amplitude:

It is the measure of height from peak to trough.

Wavelength:

It is measure of length from peak to peak.

There is no relation between the amplitude and wavelength but if the system will no more linear then high amplitude can cause the distortion in wave if more frequencies are present. However frequency and wavelength can be related. The wave with higher frequency have shorter wavelength and vise versa.

Frequency:

It is the number of waves passing through a given point in a given time period. It is measure in Hz or s⁻¹

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3 years ago

How many grams do 6.534e+24 molecules of phosphoric acid weigh?

fredd [130]

Answer:

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Explanation:

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--------------------------------------------- x ------------------------------------- x --------------
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= 1,063 grams H₃PO₄

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Zolol [24]

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2 years ago

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