I would say <span>4. 40. g at 15°C because kinetic energy is related to temperature and not mass, so the lower temp would give you lower KE</span>
Answer:
A. c. Keq=[H2]^2[S2]/[H2S]^2
B. b. Keq=[COCl2]/[CO][Cl2]
Explanation:
Hello,
In this case, considering the law of mass action which states that the equilibrium expression is written in terms of the concentration of products divided by the concentration of reactants considering the stoichiometric coefficients as powers we obtain:
A. For the reaction:

The equilibrium expression is:
![Keq=\frac{[H_2]^2[S_2]}{[H_2S]^2}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BH_2%5D%5E2%5BS_2%5D%7D%7B%5BH_2S%5D%5E2%7D)
Therefore, answer is c. Keq=[H2]^2[S2]/[H2S]^2.
B. For the reaction:

The equilibrium expression is:
![Keq=\frac{[COCl_2]}{[CO][Cl_2]}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BCOCl_2%5D%7D%7B%5BCO%5D%5BCl_2%5D%7D)
Therefore, answer is b. Keq=[COCl2]/[CO][Cl2].
Regards.
Answer:
i think interstellar dust......
Answer:
1gram of water
Explanation:
First balance the equation
Ch4+2O2>CO2+2H2O
Ratio is 1:2
500×10-3what about 2?
500×10-3×2=1g
1g of water