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2 years ago

Jerimiah spent $3.96 on 4 lollypops. what is the unit rate?

Mathematics

2 answers:

ivolga24 [154]2 years ago

8 0

Answer: 0.99 dollars per lollypop

alexandr1967 [171]2 years ago

3 0

Answer:

.92/1 for each lollypop im pretty sure this is right

Step-by-step explanation:3.69 $ ÷ 4

4 lollypops ÷ 4

0.9225 $

1 lollypop

0.9225 $

lollypop

round to .92

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2 years ago

A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li

hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote <em>R</em> as the event that a component needs rework.

It is given that:

$P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20$

Compute the probability that a randomly selected component needs rework as follows:

$P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069$

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

$P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069} =0.3623$

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

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2 years ago

Please Help...........

klasskru [66]

I believe the answer might be:
x = 28/19

Steps:
Expand
3(5 - x)/2 - 4(3 + 2x)/5

-3x + 15 - 8x + 12
------------ -----------
2 5

Find the LCD for the equation above:
(15-3x) * 5 - (12+8x) * 2
------------- --------------
10 10

Now we combine them since the denominators are equal:
5(-3+15) - 2(8x+12)
--------------------------
10

We expand above:
-31x+51
-----------
10

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3 years ago