For this case we have, by definition, that:
Resistance is a component that is responsible for limiting the amount of current that can pass through a circuit, converting excess heat.
Consume energy.
Option A represents a swicth, option B represents a luminaire and option D represents a voltage source.
So, the correct option is C,
Answer:
Option C
Answer:
Differences between freefall and weightlessness are as follows:
<h3>
<u>Freefall</u></h3>
- When a body falls only under the influence of gravity, it is called free fall.
- Freefall is not possible in absence of gravity.
- A body falling in a vacuum is an example of free fall.
<h3>
<u>Weightlessness</u></h3>
- Weightlessness is a condition at which the apparent weight of body becomes zero.
- Weightlessness is possible in absence of gravity.
- A man in a free falling lift is an example of weightlessness.
Hope this helps....
Good luck on your assignment....
Answer:
Explanation:
Of course because it's Newton's Law that if body A exerts force on body B, then body B will exert equal but opposite force on body A.
HAPPY LEARNING:)
The speed will increase four (4) times when the frequency of sound wave is increased four (4) times.
<h3>How to calculate the
frequency of a
wave.</h3>
Mathematically, the frequency of a sound wave is given by this formula:

<u>Where:</u>
- F is the frequency of a sound wave.
- V is the velocity of a sound wave.
is the wavelength of a sound wave.
<u>Note:</u> The frequency of the sound wave is increased four (4) times.
Substituting the given parameters into the formula, we have;

Therefore, the speed will increase four (4) times when the frequency of sound wave is increased four (4) times.
Read more on sound wave here: brainly.com/question/19250621
M = mass of the bowling ball = 4 kg
V = speed of bowling ball = 3.93 m/s
P = magnitude of momentum of bowling ball = ?
magnitude of momentum of bowling ball is given as
P = MV
inserting the values
P = 4 x 3.93
P = 15.72 kgm/s
m = mass of ping-pong ball = 2.293 g = 2.293 x 10⁻³ kg
v = speed of the ping-pong ball = ?
p = magnitude of momentum of ping-pong ball
Given that :
magnitude of momentum of ping-pong ball = magnitude of momentum of bowling ball
p = P
m v = 15.72
(2.293 x 10⁻³) v = 15.72
v = 6.86 x 10³ m/s