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Fofino [41]
4 years ago
8

What is the reason for each proof?

Mathematics
1 answer:
Arisa [49]4 years ago
6 0

Answer:

Step-by-step explanation:

We have given the expression:

3x - 4 = 2(x + 8)

Now multiply the R.H.S

3x-4 = 2x+16 (Distributive property)

Add 4 to both sides:

3x-4+4=2x+16+4

3x = 2x+20 (Addition property of equality)

Subtract 2x from both sides:

3x-2x = 2x-2x+20

x=20 (Subtraction property of equality)....

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Type the correct answer in the box. Use numerals instead of words if necessary use the /
Lorico [155]

Answer:

The length of the TV is 45 inches and the height is 28 inches.

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4 years ago
WHAT IS THE SOLUTION TO THIS EQUATION<br> 1. 8x - 5(x- 3)= 18
marysya [2.9K]

Answer:

x = 1

Step-by-step explanation:

8x - 5(x - 3) = 18

8x - 5x + 15 = 18   <em>[Expand the brackets]</em>

3x = 3   <em>[Separate variables and constants]</em>

<u>x = 1</u>

5 0
3 years ago
Read 2 more answers
What is the square root of 58?
Westkost [7]

Answer:

7.6

Step-by-step explanation:

6 0
3 years ago
−3(2+4k)+7(2k−1) eqivalent expression
Alex17521 [72]

Answer:

\large\boxed{-3(2+4k)+7(2k-1)=2k-13}

Step-by-step explanation:

-3(2+4k)+7(2k-1)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=(-3)(2)+(-3)(4k)+(7)(2k)+(7)(-1)\\\\=-6-12k+14k-7\qquad\text{combine like terms}\\\\=(-12k+14k)+(-6-7)\\\\=2k-13

6 0
3 years ago
The vertices of a right triangle are (0, 0), (1, 0), and (0, 1).
Alchen [17]

Answer:

(3,3)

Step-by-step explanation:

Given

Vertices: (0,0)\ (1,0)\ (0,1)

Scale\ Factor = 3

Required

Determine which can't be any of the new vertices

First, we need to determine the new vertices:

New\ Vertex = Scale\ Factor * Old\ Vertex

For (0,0):

New\ Vertex = 3 * (0,0)

New\ Vertex = (3 * 0,3 * 0)

New\ Vertex = (0,0)

For (1,0):

New\ Vertex = 3 * (1,0)

New\ Vertex =  (3 * 1,3 * 0)

New\ Vertex =  (3,0)

For (0,1):

New\ Vertex =  3 * (0,1)

New\ Vertex =  (3 * 0,3 * 1)

New\ Vertex =  (0,3)

<em>Comparing the calculated new vertices to the list of given options; (3,3) can't be any of the new vertices of the new triangle</em>

<em></em>

5 0
4 years ago
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