1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VARVARA [1.3K]
4 years ago
6

Valuable ore deposits and gem crystals are often associated with _____. a. oceans b.oil deposits c. thin crustal areas d. igneou

s intrusions   Which of the following shows a possible sequence that leads to the formation of sedimentary rocks? a. squeezing, heating, bending, folding b. rising, weathering, erosion c. weathering deposition, compaction, cementation d. melting, cooling, crystallization   PLZ HELP!! :)
Chemistry
2 answers:
elixir [45]4 years ago
3 0
For the first question:
Valuable ore deposits and gem crystals are often associated with igneous intrusions. So for this question the correct option is option “d”. An example like the Pegmatite’s, which are a form of igneous intrusions, is responsible for the creation of variety of gems like topaz and tourmaline.
For the second question:
For this specific question, option “c” seems to be the correct option. Weathering, deposition, compaction, cementation are the possible sequence that leads to the formation of sedimentary rocks.





aleksandr82 [10.1K]4 years ago
3 0

Answer:

for the first one its D.

For the second one its C.

There you go.

You might be interested in
How would you prepare 500 mL of 0.360 M solution of CaCl2 from<br> solid CaCl2?
LenKa [72]

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

0.500 L \times \frac{0.360mol}{L} = 0.180 mol

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

0.180 mol \times \frac{110.98g}{mol} = 20.0 g

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

You can learn more about solutions here: brainly.com/question/2412491

4 0
2 years ago
What do the numbers listed for an element on the periodic table represent?
Anna007 [38]
The smaller number is the number of protons, and the greater number is the mass.
8 0
3 years ago
Read 2 more answers
50 Points <br> Look at the image below
Vadim26 [7]

Answer:

B-Sucrose molecules are too large to conduct electricity in once dissolved in water.

D-Salts, like NaCL, have ionic bonds and are considered to be electrolytes:when dissolved in water, salts dissociate and form ions.

Explanation:

6 0
3 years ago
Read 2 more answers
How many grams are in 1.76 x 10^23 atoms of iodine
Mariana [72]

Answer:

\boxed {\boxed {\sf About \ 37.1 \ grams \ of \ iodine }}

Explanation:

To convert from atoms to grams, you must first convert atoms to moles, then moles to grams.

1. Convert Atoms to Moles

To convert atoms to grams, Avogadro's number must be used.

6.022*10^{23}

This number tells us the number of particles (atoms, molecules, ions, etc.) in 1 mole. In this case, the particles are atoms of iodine.

\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Multiply the given number of atoms by Avogadro's number.

1.76*10^{23} \ atoms \ I*\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Flip the fraction so the atoms of iodine will cancel out.

1.76*10^{23} \ atoms \ I*\frac{  1 \ mol \ I}{6.022*10^{23} \ atoms \ I}

1.76*10^{23}* \frac{1 \ mol \ I}{6.022*10^{23} }

Multiply so the problem condenses into 1 fraction.

\frac{1.76*10^{23} \ mol \ I}{6.022*10^{23} }

0.2922617071 \ mol \ I

2. Convert Moles to Grams

Now we must use the molar mass of iodine, which is found on the Periodic Table.

  • Iodine Molar Mass: 126.9045 g/mol

Use this mass as a fraction.

\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply this fraction by the number of moles found above.

0.2922617071 \ mol \ I*\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply. The moles of iodine will cancel.

0.2922617071 *\frac{ 126.9045 \ g\ I }{ 1 }

The 1 as a denominator is insignificant.

0.2922617071 *{ 126.9045 \ g\ I }

37.08932581 \ g \ I

3. Round

The original measurement of 1.76*10^23 has 3 significant figures (1, 7, and 6). Therefore we must round our answer to 3 sig figs. For this answer, that is the tenths place.

37.08932581 \ g \ I

The 8 in the hundredth place tells us to round the 0 up to a 1.

\approx 37.1\ g \ I

There is about <u>37.1 grams of iodine </u>in 1.76*10^23 atoms.

5 0
3 years ago
Which information is revealed in a chemical formula?
wariber [46]
I think the answer is B
7 0
3 years ago
Read 2 more answers
Other questions:
  • What are two ways in which an ion could be nade
    15·1 answer
  • What is the number of electrons in the highest occupied energy level of an element in Group 5A?
    14·1 answer
  • Which factors will result in a stronger ionic bond overall?a. larger ions b. similarity of ionic sizes c. greater absolute charg
    8·1 answer
  • What is the mass of 80.0mL of ethanol at 20 degress celcius
    6·1 answer
  • In the United States, which assessment system measures inflation?
    13·1 answer
  • WHAT DOES THIS SAY AND WHAT THE ANSWER
    8·1 answer
  • Describe and explain one piece of evidence that a chemical reaction occurs when baking soda is added to vinegar
    14·1 answer
  • How are the aurora borealis formed?
    5·1 answer
  • Which compound is ionic?<br> 1. CaBr2 <br> 2. NO2<br> 3. CH4<br> 4. NBr3
    14·1 answer
  • FILL IN THE BLANK! ILL GIVE BRAINLIEST The heat trapping nature of__and other gases was demonstrated in the mid 19th century
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!