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1 year ago

A resource is being used by a population.

Chemistry

2 answers:

jonny [76]1 year ago

5 0

Answer:

Graph A.

Explanation:

Graph

It represents a constant function

Jobisdone [24]1 year ago

3 0

Answer:

graph c

Explanation:

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What are the two forces that battle within a star ?

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Gravity and Thermal pressure

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4 years ago

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What types of R groups can exist in amino acids? (Choose all that apply)

PilotLPTM [1.2K]

Answer:

acidic,non polar,basic

Explanation:

that’s the ones I put and I got a 100% on my test just now

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3 years ago

We love blasting our radio in the morning to wake up. Radio waves are used to transmit information on various channels. Calculat

Reil [10]

Answer:

wavelength = 0.56 × 10⁻² m

Explanation:

Given data:

Frequency of radiation = 5.4 × 10¹⁰ Hz

Wavelength = ?

Solution:

Formula:

speed of light = wavelength × frequency

wavelength = speed of light / frequency

wavelength = 3 × 10⁸ m/s / 5.4 × 10¹⁰ Hz ( Hz= 1/s)

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4 years ago

The coefficient of thermal expansion α = (1/V)(∂V/∂T)p. Using the equation of state, compute the value of α for an ideal gas. Th

andreyandreev [35.5K]

Answer:

The coefficient of thermal expansion α is

$\alpha = \frac{1}{T}$

The coefficient of compressibility

$\beta = \frac{1}{P}$

Now considering $(\frac{ \delta P }{\delta T} )V$

From equation (1) we have that

$\frac{ \delta P}{\delta T} = \frac{n R }{V}$

From ideal equation

$nR = \frac{PV}{T}$

$\frac{\delta P}{\delta T} = \frac{PV}{TV}$

=> $\frac{\delta P}{\delta T} = \frac{P}{T}$

=> $\frac{\delta P}{\delta T} = \frac{\alpha }{\beta}$

Explanation:

From the question we are told that

The coefficient of thermal expansion is $\alpha = \frac{1}{V} * (\frac{\delta V}{ \delta P}) P$

The coefficient of compressibility is $\beta = - (\frac{1}{V} ) * (\frac{\delta V}{ \delta P} ) T$

Generally the ideal gas is mathematically represented as

$PV = nRT$

=> $V = \frac{nRT}{P} --- (1)$

differentiating both side with respect to T at constant P

$\frac{\delta V}{\delta T } = \frac{ n R }{P}$

substituting the equation above into $\alpha$

$\alpha = \frac{1}{V} * ( \frac{ n R }{P}) P$

$\alpha = \frac{nR}{PV}$

Recall from ideal gas equation $T = \frac{PV}{nR}$

$\alpha = \frac{1}{T}$

Now differentiate equation (1) above with respect to P at constant T

$\frac{\delta V}{ \delta P} = -\frac{nRT}{P^2}$

substituting the above equation into equation of $\beta$

$\beta = - (\frac{1}{V} ) * (-\frac{nRT}{P^2} ) T$

$\beta =\frac{ (\frac{n RT}{PV} )}{P}$

Recall from ideal gas equation that

$\frac{PV}{nRT} = 1$

$\beta = \frac{1}{P}$

Now considering $(\frac{ \delta P }{\delta T} )V$

From equation (1) we have that

$\frac{ \delta P}{\delta T} = \frac{n R }{V}$

From ideal equation

$nR = \frac{PV}{T}$

$\frac{\delta P}{\delta T} = \frac{PV}{TV}$

=> $\frac{\delta P}{\delta T} = \frac{P}{T}$

=> $\frac{\delta P}{\delta T} = \frac{\alpha }{\beta}$

5 0

3 years ago

What mass of KCL is contained in .350 M solution of KCL?

Sergio039 [100]

The mass of KCl per volume of solution=.35X(35.5+39)=26.075g/L

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4 years ago