motion
vt=vo+at
10 m/s = 2 m/s + 2.2 m/s².t
8 = 2.2t
![\tt t=\dfrac{8}{2.2}=3.63~s](https://tex.z-dn.net/?f=%5Ctt%20t%3D%5Cdfrac%7B8%7D%7B2.2%7D%3D3.63~s)
Answer:
<h2>C) internal combustion engine</h2>
Explanation:
Answer:
increases.
Explanation:
As a ball falls freely towards the ground, it's kinetic energy increases. If the kinetic energy increases, that means the object hasn't hit the bottom yet. If the ball continues to fall freely towards the ground, the air gives it more pressure, after that the pressure begins to increase.
An experimental variable is a variable that is being tested to answer a scientific question; while a control variable is a variable that is not being altered or changed during the experiement to serve as a constant. An example of an experimental variable is plant food solution A and whether it makes a kidney bean sprout faster than plant food solution B. An example of a control variable is water, because there is no plant food mixed in to create a solution; so it will serve as a natural constant.
Answer:
a material with a large specific heat can absorb a great deal of thermal energy without a great change in temperature.
Explanation:
The specific heat capacity of an object is the amount of energy needed to raise the temperature of 1 kg of mass of a substance by
.
Mathematically, it is given by:
![C=\frac{Q}{m\Delta T}](https://tex.z-dn.net/?f=C%3D%5Cfrac%7BQ%7D%7Bm%5CDelta%20T%7D)
where
Q is the amount of energy supplied
m is the mass of the substance
is the change in temperature of the substance
The equation can be rewritten as:
![\Delta T=\frac{Q}{mC}](https://tex.z-dn.net/?f=%5CDelta%20T%3D%5Cfrac%7BQ%7D%7BmC%7D)
Therefore, we see that the increase in temperature of a substance is inversely proportional to its specific heat capacity.
Therefore, a material with a large specific heat can absorb a great deal of thermal energy without a great change in temperature.