I assume friction is the only force acting on the book as it slides.
(A) By the work-energy theorem, the total work performed on the book as it slides is equal to the change in its kinetic energy:
<em>W</em> = ∆<em>K</em>
<em>W</em> = 1/2 (1.50 kg) (1.25 m/s)² - 1/2 (1.50 kg) (3.21 m/s)²
<em>W</em> ≈ -6.56 J
(B) Using the work-energy theorem again, the speed <em>v</em> of the book at point C is such that
-0.750 J = 1/2 (1.50 kg) <em>v</em> ² - 1/2 (1.50 kg) (1.25 m/s)²
==> <em>v</em> = 0.750 m/s
(C) Take the left side to be positive, then solve again for <em>v</em>.
0.750 J = 1/2 (1.50 kg) <em>v</em> ² - 1/2 (1.50 kg) (1.25 m/s)²
==> <em>v</em> ≈ 1.60 m/s
Answer:
An increase in the mass on the string will cause an increase in the period.
Explanation:
We'll begin by writing an expression showing the relationship between the period and mass. This is shown below:
T = 2π√(m/K)
Where:
T is the period of oscillation.
m is the mass of the object.
K is the spring constant.
T = 2π√(m/K)
From the above formula:
The period (T) is directly proportional to the square root of mass (m) and inversely proportional to the square root of the spring constant (K). This implies that an increase in the mass of the object on the spring will result in an increase in the period of oscillation and a decrease in the mass of the object will also decrease the period of oscillation.
Carter needs a power equal to 63 W to be able to push the bag full of Jersey. This is by using the formula: Power is equal to the product of Force applied and Displacement all over time traveled.
Given:-
- Mass of the cart (m) = 35 kg
- Speed (consider Velocity) = 1.2 m/s
To Find: Momentum of the cart.
We know,
p = mv
where,
- p = Momentum,
- m = Mass &
- v = Velocity.
Thus,
p = (35 kg)(1.2 m/s)
→ p = 42 kg m/s (Ans.)
Conclusion:-
A. ☑️ 42 kilogram - metre per second.
