Ask question

Ask question

All categories

ludmilkaskok [199]

3 years ago

11

An average human weighs about 650 N. If each of two average humans could carry 1.0 C of excess charge, one positive and one nega

tive, how far apart would they have to be for the electric attraction between them to equal their [email protected] weight?

1 answer:

bezimeni [28]3 years ago

5 0

Answer:

Distance, r = 3721.04 meters

Explanation:

It is given that,

Charges on both humans, $q_1=q_2=1\ C$

Electric force of attraction between them, F = 650 N

We need to find the separation between two humans. It can be solved using the following formula as :

$F=\dfrac{kq^2}{r^2}$

$r=\sqrt{\dfrac{kq^2}{F}}$

$r=\sqrt{\dfrac{9\times 10^9\times (1)^2}{650}}$

r = 3721.04 meters

So, the distance between the humans is 3721.04 meters. Hence, this is the required solution.

You might be interested in

How are the strong winds associated with the tornado in diagram C product

Paul [167]

Answer:

there is no diagram, but i can try to help

Explanation:

strong winds bonding together (i.e hot and cold) help form the tornado, depending on the weather depends on how long it can go on, if more hot and cold are feeds into it, it will get faster and last longer. it is just like dust devils, it is wind and dirt mixing to make a tornado, the more wind and dirt the worst it will be

4 0

3 years ago

A particle undergoes two displacements. The first has a magnitude of 11 m and makes an angle of 82 ◦ with the positive x axis. T

Luden [163]

Answer:

$\theta = 211.7 degree$

Explanation:

First displacement of the particle is given as

$r_1$ = 11 m at 82 degree with positive X axis

so we can say

$\vec r_1 = 11 cos82 \hat i + 11 sin82 \hat j$

$\vec r_1 = 1.53\hat i + 10.9 \hat j$

resultant displacement of the particle after second displacement is given as

r = 8.7 m at 135 degree with positive X axis

so we can say

$r = 8.7 cos135\hat i + 8.7 sin135\hat j$

$r = -6.15 \hat i + 6.15 \hat j$

now we know that

$r = r_1 + r_2$

now we have

$r_2 = r - r_1$

so we will have

$r_2 = (-6.15 \hat i + 6.15 \hat j) - (1.53\hat i + 10.9 \hat j)$

$r_2 = -7.68 \hat i - 4.75 \hat j$

so angle of the second displacement is given as

$tan\theta = \frac{r_y}{r_x}$

$tan\theta = \frac{-4.75}{-7.68}$

$\theta = 211.7 degree$

8 0

3 years ago

a light object and a heavy object have the same kinetic energy. which has the greater momentum? explain.

vodomira [7]

The kinetic energies of a light and a heavy body are equivalent. The momentum is greater for the light body.

<h3>What is momentum?</h3>

Momentum is characterized as the intensity of a body's motion. As momentum depends on both velocity and the direction of the body's motion, it is quantified by "mass velocity". Since velocity is a vector and mass is a scalar, momentum is a vector quantity.

As a result of its higher mass, a heavy object will move with more momentum. Only when the average speed of the heavy particles is lower than that of the light particles will the average kinetic energy of the light particles equal the average kinetic energy of the heavy particles.

At the same temperature and pressure, lighter gases will move more quickly than heavier ones. 0K on the Kelvin scale denotes that the particles are not moving.

To learn more about momentum refer to:

brainly.com/question/1042017

#SPJ4

5 0

2 years ago

The orbital motion of Earth around the Sun leads to an observable parallax effect on the nearest stars. For each star listed, ca

Murrr4er [49]

Answer:

Following are the answer to this question:

Explanation:

Formula:

$D(PC) =\frac{1}{parallax}\\\\D(av)=D(PC) \times 20.626\ J$

Calculating point A:

when the value is $0.38$

$\to 0.38 \toD(PC)= \frac{1}{0.38}\\\\$

$=2.632$

$\to D(a.v) = \frac{1}{0.38} \times 206265\\$

$=542,802.6$

Calculating point B:

when the value is $0.75$

$\to D(PC)=\frac{1}{0.75}$

$=1.33$

$\to D(a.v) = \frac{1}{0.75} \times 206265\\$

$=275,020$

Calculating point C:

when the value is $0.28$

$\to D(PC)=\frac{1}{0.28}$

$=3.571$

$\to D(a.v) = \frac{1}{0.28} \times 206265\\$

$=736660.7$

Calculating point D:

when the value is $0.42$

$\to D(PC)=\frac{1}{0.42}$

$=2.38$

$\to D(a.v) = \frac{1}{0.42} \times 206265\\$

$=490910.7$

Calculating point E:

when the value is $0.31$

$\to D(PC)=\frac{1}{0.31}$

$=3.226$

$\to D(a.v) = \frac{1}{0.31} \times 206265\\$

$=665370.97$

6 0

3 years ago

a 905 - g meteor impacts the earth at a speed of 1623 m/s. if all of its energy is entirely converted to heat in the meteor, wha

nlexa [21]

Answer: 2859.78 k

Explanation: By using the law of conservation of energy, the kinetic energy of the meteor equals the heat energy.

Kinetic energy = 1/2mv^2

Heat energy = mcΔθ

Where m = mass of meteor , v = velocity of meteor = 1623 m/s

c = specific heat capacity of meteor (iron) = 460.548 j/kg/k

Δθ = change in temperature of meteor = ?

From law ofconservation of energy, we have that

1/2mv^2 = mcΔθ

By cancelling "m" on both sides, we have that

v^2/2 = cΔθ

v^2 = 2cΔθ

(1623)^2 = 2× 460.548 × Δθ

2634129 = 921.096 × Δθ

Δθ = 2634129 / 921.096

Δθ = 2859.78 k

6 0

3 years ago