Question

Calculate the capacitance of a system that stores 9.4 x 10-10 C of charge at

Answer 1

Answer:

A. $1.88\times 10^{-11}\,F$.

Explanation:

By definition of Electric Capacitance, the capacitance of the system ($C$), in farads, is described by the following formula:

$C = \frac{q}{V}$ (1)

Where:

$q$ - Electric charge, in coulombs.

$V$ - Voltage, in volts.

If we know that $q = 9.4\times 10^{-10}\,C$ and $V = 50\,V$, then the capacitance of the system is:

$C = \frac{9.4\times 10^{-10}\,C}{50\,V}$

$C = 1.88\times 10^{-11}\,F$

The correct answer is A.