Answer:
it is -67
Step-by-step explanation:
Answer:
sorry tried to help computer would not let me
Step-by-step explanation:
Answer:
A) JK and AB =
![[tex] \boxed{( \theta) = \f{12}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%5Cf%7B12%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, =》 
=》 
[/tex]
B) AABC
![[tex] \boxed{( \theta) = {1}{( \theta)} }](https://tex.z-dn.net/?f=%5Btex%5D%20%5Cboxed%7B%28%20%5Ctheta%29%20%3D%20%7B1%7D%7B%28%20%5Ctheta%29%7D%20%7D)
So, 
C) AABM:
![[tex] e \fbox{: }](https://tex.z-dn.net/?f=%5Btex%5D%20e%20%5Cfbox%7B%3A%20%7D)
The value of k for which 
is 
ans[/tex]
----------
Answer:
528 cm²
Step-by-step explanation:
The surface area of this prism comprises:
- 2 congruent triangles (the bases of the prism)
- 2 congruent rectangles (rectangle 1 and 2) - since the triangle has 2 sides of equal length
- 1 rectangle (rectangle 3)
Area of a triangle = 1/2 × base × height
= 1/2 × 16 × 6
= 48 cm²
Area of rectangle 1 / 2 = width × length
= 10 × 12
= 120 cm²
Area of rectangle 3 = width × length
= 16 × 12
= 192 cm²
Total Surface Area = 2 triangles + 2 rectangles + rectangle 3
= (2 × 48) + (2 × 120) + 192
= 96 + 240 + 192
= 528 cm²
