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3 years ago

Someone please help me I need it ASAP

Mathematics

2 answers:

Sauron [17]3 years ago

5 0

Answer:

You need four squares.

On the top left square, you put the number 20 over it, and the number 30 to it's left. Put the number 600 in the square.

Next, the bottom left square. But the number 8 on the left side of the square, and put the number 160 in the square.

Now, the top right box. put the number 4 over it, and fill it with the number 120.

Last, fill the bottom right square with the number 32.

drek231 [11]3 years ago

3 0

Answer: 952

Step-by-step explanation:

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The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev

Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 30.05 inches

$\sigma$ = standard deviation = 0.2 inches

n = sample of sheets = 4

So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches) = P(X bar < 30.35) - P(X bar <= 30.25)

P(X bar < 30.35) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{30.35-30.05}{\frac{0.2}{\sqrt{4} } }$ ) = P(Z < 3) = 0.99865

P(X bar <= 30.25) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{30.25-30.05}{\frac{0.2}{\sqrt{4} } }$ ) = P(Z <= 2) = 0.97725

Therefore, P(30.25 inches < X bar < 30.35 inches) = 0.99865 - 0.97725

= 0.0214

7 0

3 years ago

Find the volume and round to the nearest tenth as needed

erastovalidia [21]

Answer:

1053 m^3

Step-by-step explanation:

Pyramid top 1/3 * 9 * 9 * 12 = 324 m^3

Base 9 * 9 * 9 = 729 m^3

total 1053 m^3

6 0

2 years ago

Oliver works at a book store.He packed 20 identical paperbacks and 9 identical textbooks in a box .The total mass of the book wa

Natasha_Volkova [10]

Let x be the mass of the paperbacks and y be the mass of the textbook.

20x + 9y = 44.4 ----------- (1)
25x + 10y = 51 -------------(2)

(1) x 10:
200x + 90y = 444 --------(1a)

(2) x 9:
225x + 90y = 459 --------(2a)

(2a) - (1a):
25x = 15
x = 0.6 -------- sub into (1)

20 (0.6) + 9y = 44.4
12 + 9y = 44.4
9y = 44.4 - 12
9y = 32.4
y = 3.6

So the paperback's mass is 0.6 pounds and textbook is 3.6 pounds

7 0

3 years ago

Which of the following are valid probability distributions?

Anvisha [2.4K]

Answer:

Step-by-step explanation:

6 0

3 years ago

HELP ME PLEASE <br> solve the right triangle

Amiraneli [1.4K]

ST = 7.2

RT = 4.04