Answer:
Luis has 30 cards
Step-by-step explanation:
To solve this problem, we need to setup a system of equations.
If we call the amount of cards Juan has "J", Pedro "P", Maria "M" and Luis "L", we have that:
J + P + M + L = 62
P = J/3
M = J - 3
L = 2J
Substituting P, M and L in the first equation, we have:
J + J/3 + J - 3 + 2J = 62
13J/3 = 62 + 3
13J = 65 * 3
J = 15 cards
The amount of cards Luis has is:
L = 2J = 2 * 15 = 30 cards
Answer:
The perimeter of the square is 
Step-by-step explanation:
step 1
Find the length side of the square
we know that
The area of a square is equal to

where
b is the length side of the square
we have

substitute and solve for b

square root both sides

step 2
Find the perimeter of the square
we know that
The perimeter of the square is equal to

we have

substitute


If the triangle has a angle of 90°, you can solved this exercise by applying the Pythagorean Theorem, which is:
h²=a²+b²
h=√(a²+b²)
h: It is the hypotenuse
(The opposite side of the right angle and the longest side of the triangle).
a and b: They are the legs
(The sides that form the right angle).
The result of h=√(a²+b²), should be 17.1 (The longest side given in the problem). So, let's substitute the values of the legs into the Pythagorean equation:
h=√(a²+b²)
h=√((9.2)²+(14.5)²)
h=17.1
Therefore, the answer is:
Yes, the given measures can be the lengths of the sides of a triangle.
Answer:
The distance of the point from the origin = 9.29 units.
Step-by-step explanation:
Given point:
(7,-6)
The angle lies such that the terminal side of the angle contains the given point.
To draw the angle and find the distance from the origin to the given point.
Solution:
The terminal side of the angle is where the angle ends with the initial side being the positive side of the x-axis.
So, we can plot the point (7,-6) by moving 7 units on the x-axis horizontally and -6 units on the y-axis vertically.
We can find the distance of the point from the origin by find the hypotenuse of the triangle formed.
Applying Pythagorean theorem.



Taking square root both sides :


Thus, the distance of the point from the origin = 9.29 units.
The figure is shown below.
All you need to do is plug in some x values and find the correspoding y value
when x=0, y=-3
when x=1, y=9
when x=2, y=21
when x=-1, y=-15