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Ber [7]
3 years ago
12

Simplify this problem: 32‾‾‾√

Mathematics
1 answer:
Vesnalui [34]3 years ago
7 0

Answer:

4\sqrt{2}

Step-by-step explanation:

If you are asking for:

\sqrt{32}

You can pull out 16 from the equation and you can get:

4\sqrt{2}

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5 0
2 years ago
Will crown the correct answers brainliest 3x
Solnce55 [7]

Answer :

(1) \frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}

(2) \frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{15xy}

(3) \frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{14xy}

(4) \frac{2}{5x}+\frac{3}{7y}=\frac{6y+15x}{21xy}

(5) \frac{7}{11x}-\frac{1}{33y}=\frac{231y-11x}{363xy}

(6) \frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{7y+42y-2x}{14xy}

Step-by-step explanation :

(1) The given expression is: \frac{1}{x}+\frac{1}{y}

\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}

(2) The given expression is: \frac{1}{5x}+\frac{1}{3y}

\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{(5x)\times (3y)}=\frac{3y+5x}{15xy}

(3) The given expression is: \frac{1}{7x}-\frac{1}{2y}

\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{(7x)\times (2y)}=\frac{2y-7x}{14xy}

(4) The given expression is: \frac{2}{5x}+\frac{3}{7y}

\frac{2}{5x}+\frac{3}{7y}=\frac{(2\times 3y)+(3\times 5x)}{(5x)\times (7y)}=\frac{6y+15x}{21xy}

(5) The given expression is: \frac{7}{11x}-\frac{1}{33y}

\frac{7}{11x}-\frac{1}{33y}=\frac{(7\times 33y)-(1\times 11x)}{(11x)\times (33y)}=\frac{231y-11x}{363xy}

(6) The given expression is: \frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}

\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{(x\times 7y)+(3\times 2x\times 7y)-(2x\times x)}{(2x)\times (x)\times (7y)}=\frac{7xy+42xy-2x^2}{14x^2y}=\frac{7y+42y-2x}{14xy}

7 0
2 years ago
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