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sergey [27]
3 years ago
10

Which of the following best defines the term oxidation state?

Chemistry
1 answer:
eimsori [14]3 years ago
4 0
C seems to be the best answer

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If all three metals were exposed to extremely high temperatures, which would be the last to melt?
Verdich [7]
Copper would be the last to melt because it has the highest melting point!
3 0
2 years ago
Read 2 more answers
What are the similarities and differences between ionic and covalent bonds?
ohaa [14]

Answer:

Explanation:

Similarities.

Both Ionic and covalents bond produce exothermic reactions.

They are both neutral.in Ionic bonds, the two opposite charge will terminate each other and in covalent, the neutral molecules tend to share electrons.

Difference

Ionic bonds have high polarity while covalent have low.

Ionic bonds have no definite shape, covalent have.

Ionic have high melting points, covalent have low.

Io ic have high boiling point, covalents have low.

5 0
3 years ago
The balanced equation for the reaction of ammonia and oxygen is the following. 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) The stand
ale4655 [162]

Answer:

ΔS° = 180.5 J/mol.K

Explanation:

Let's consider the following reaction.

4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g)

The standard molar entropy of the reaction (ΔS°) can be calculated using the following expression.

ΔS° = ∑np × S°p - ∑nr × S°r

where,

ni are the moles of reactants and products

S°i are the standard molar entropies of reactants and products

ΔS° = 4 mol × S°(NO(g)) + 6 × S°(H₂O(g)) - 4 mol × S°(NH₃(g)) - 5 mol × S°(O₂(g))

ΔS° = 4 mol × 210.8 J/K.mol + 6 × 188.8 j/K.mol - 4 mol × 192.5 J/K.mol - 5 mol × 205.1 J/K.mol

ΔS° = 180.5 J/K

This is the change in the entropy per mole of reaction.

7 0
3 years ago
Who were good friends in one day a stranger came<br><br>​
insens350 [35]

Answer:

???

Explanation:

5 0
3 years ago
When 12 moles of methanol (ch3oh) and 24 moles of oxygen gas react according to the chemical equation below, what is the limitin
Nataliya [291]
The balanced reaction equation for the reaction between CH₃OH and O₂ is 
                        2CH₃OH(l) + 3O₂(g) → 2CO₂(g) + 4H₂O(l)
Initial moles        12                24
Reacted moles   12                18
Final moles          -                   6              12               24
 
The stoichiometric ratio between CH₃OH and O₂ is 2 : 3
Hence,
   reacted moles of O₂ = reacted moles of CH₃OH x (3/2)
                                      = 12 mol x 3 / 2  
                                      = 18 mol

All of CH₃OH moles react with O₂.

Hence, the limiting agent is CH₃OH. 

Excess reagent is O₂.
Amount of moles of excess reagent left = 24 - 18 mol = 6 mol
                                            
5 0
3 years ago
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