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3 years ago

why a gas, at constant pressure, increases greatly in volume when it is gently heated but a solid does not

Chemistry

1 answer:

11Alexandr11 [23.1K]3 years ago

8 0

Explanation:

This is because gas particles are free to move as they are not held in place by strong molecular forces while particles in a solid are

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Differentiate between Mendeleev's Period law and Modern Periodic law<br>

NeX [460]

<h2>see in the attachment hope it helps you</h2>

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2 years ago

PLEASE HELP & SHOW WORK

Olegator [25]

Answer:

1. 0.178 moles ; 2. 8x10²³ atoms ; 3. 7.22x10²³ molecules ; 4. 89.6 g ; 5. 1.34x10²² atoms ; 6. 1.67x10²⁵ molecules

Explanation:

1. Mass / Molar mass = Mol

5g / 28 g/m = 0.178 moles

2. 1 molecule of N₂ has 2 atoms, it is a dyatomic molecule.

4x10²³ x2 = 8x10²³ atoms

3. 1 mol of anything, has 6.02x10²³ particles

6.02x10²³ molecules . 1.2 mol = 7.22x10²³

4. 1 atom of C weighs 12 amu.

4.5x10²⁴ weigh ( 4.5x10²⁴ . 12) = 5.24x10²⁵ amu

1 amu = 1.66054x10⁻²⁴g

5.24x10²⁵ amu = (5.24x10²⁵ . 1.66054x10⁻²⁴) = 89.6 g

5. Molar mass NaCl = 58.45 g/m

1.3 g / 58.45 g/m = 0.0222 moles

1 mol has 6.02x10²³ atoms

0.0222 moles → ( 0.0222 . 6.02x10²³) = 1.34x10²²

6. Density of water is 1 g/mL, so 500 mL are contained in 500 g of water

Molar mass H₂O = 18 g/m

500 g / 18 g/m = 27.8 moles

6.02x10²³ molecules . 27.8 moles = 1.67x10²⁵

8 0

3 years ago

Part A

velikii [3]

Answer: The layers are ordered by density, with the least dense layer on top, and the densest layer on the bottom.

Explanation:

Plato

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3 years ago

True or False: Both molecules and compounds are pure substances.

Solnce55 [7]

Answer:

False

Explanation:

Hope this helps!

4 0

2 years ago

Read 2 more answers

A solution of an unknown nonvolatile nonelectrolyte was prepared by dissolving 0.250 g of the substance in 40.0 g of ccl4. the b

Finger [1]

Answer : The molar mass of the solute will be 87.90 g/mol.

Explanation : We know the formula for elevation in boiling point, which is

Δt = i $K_{b}$ m

given that, Δt = 0.357, $K_{b}$ = 5.02 and mass of $CCl _{4}$ = 40,

on substituting the value we get,
0.357 = (1) X (5.02) X (x/ 0.044), on solving we get x = 2.844 X $10^{-3}$ .
Now, 0.250/ 2.844 X $10^{-3}$ = 87.90 g/mol. which is the weight of unknown component.

3 0

3 years ago