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2 years ago

Determine the concentration of NO3− in each aqueous solution. (Assume complete dissociation of each compound.)

Chemistry

1 answer:

anyanavicka [17]2 years ago

8 0

Answer:

A) The concentration of NO₃⁻ is 0.30 M

B) The concentration of NO₃⁻ is 0.60 M

C) The concentration of NO₃⁻ is 0.90 M

Explanation:

Hi there!

Let´s write the chemical equation for every dissociation reaction:

A) KNO₃ → K⁺ + NO₃⁻

Since 1 mol of KNO₃ produces 1 mol of NO₃⁻, 0.3 mol will produce 0.3 mol NO₃⁻. Then, the concentration of NO₃⁻ will be 0.30 M.

B) Ca(NO₃)₂ → Ca²⁺ + 2NO₃⁻

1 mol of Ca(NO₃)₂ produces 2 mol of NO₃⁻, then, the concentration of NO₃⁻ will be twice the concentration of Ca(NO₃)₂, that is, 0.60 M.

C) Cr(NO₃)₃ → Cr³⁺ + 3NO₃⁻

1 mol of Cr(NO₃)₃ produces 3 mol of NO₃⁻, then, if we have 0.30 mol per liter of Cr(NO₃)₃, we will have 0.90 mol per liter of NO₃⁻

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Phosgene, a poisonous gas, when heated will decompose into carbon monoxide and chlorine in a reversible reaction: COCl2 (g) <

Advocard [28]

Answer:

8.08 × 10⁻⁴

Explanation:

Let's consider the following reaction.

COCl₂(g) ⇄ CO (g) + Cl₂(g)

The initial concentration of phosgene is:

M = 2.00 mol / 1.00 L = 2.00 M

We can find the final concentrations using an ICE chart.

COCl₂(g) ⇄ CO (g) + Cl₂(g)

I 2.00 0 0

C -x +x +x

E 2.00 -x x x

The equilibrium concentration of Cl₂, x, is 0.0398 mol / 1.00 L = 0.0398 M.

The concentrations at equilibrium are:

[COCl₂] = 2.00 -x = 1.96 M

[CO] = [Cl₂] = 0.0398 M

The equilibrium constant (Keq) is:

Keq = [CO].[Cl₂]/[COCl₂]

Keq = (0.0398)²/1.96

Keq = 8.08 × 10⁻⁴

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2 years ago

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Answer:

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2 years ago

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If 21.00 mL of a 0.68 M solution of C6H5NH2 required 6.60 mL of the strong acid to completely neutralize the solution, what was

Andru [333]

Answer:

pH = 2.46

Explanation:

Hello there!

In this case, since this neutralization reaction may be assumed to occur in a 1:1 mole ratio between the base and the strong acid, it is possible to write the following moles and volume-concentrations relationship for the equivalence point:

$n_{acid}=n_{base}=n_{salt}$

Whereas the moles of the salt are computed as shown below:

$n_{salt}=0.021L*0.68mol/L=0.01428mol$

So we can divide those moles by the total volume (0.021L+0.0066L=0.0276L) to obtain the concentration of the final salt:

$[salt]=0.01428mol/0.0276L=0.517M$

Now, we need to keep in mind that this is an acidic salt since the base is weak and the acid strong, so the determinant ionization is:

$C_6H_5NH_3^++H_2O\rightleftharpoons C_6H_5NH_2+H_3O^+$

Whose equilibrium expression is:

$Ka=\frac{[C_6H_5NH_2][H_3O^+]}{C_6H_5NH_3^+}$

Now, since the Kb of C6H5NH2 is 4.3 x 10^-10, its Ka is 2.326x10^-5 (Kw/Kb), we can also write:

$2.326x10^{-5}=\frac{x^2}{0.517M}$

Whereas x is:

$x=\sqrt{0.517*2.326x10^{-5}}\\\\x=3.47x10^-3$

Which also equals the concentration of hydrogen ions; therefore, the pH at the equivalence point is:

$pH=-log(3.47x10^{-3})\\\\pH=2.46$

Regards!

6 0

2 years ago

Jose times how long sugar takes to dissolve in warm water. he conducts four trials of his experiment. what should he conclude fr

mylen [45]

He can conclude that his experiment has very low precision.

<h3>What is Precision ?</h3>

Precision is defined as the degree of refinement with which an operation is performed or a measurement .

Precision is how close the exact answers are together.

As, the answers are increasing in time.

None of the answers are similar to one another.

Hence, He can conclude that his experiment has very low precision.

Learn more about Precision here ;

brainly.com/question/27845433

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1 year ago