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uranmaximum [27]
3 years ago
8

Which of the following instrument would you use to see a plant cell?

Chemistry
2 answers:
olya-2409 [2.1K]3 years ago
7 0
B) is use too see plant cells
Gemiola [76]3 years ago
3 0
B . microscope
this is the answer .
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Has any one done 2020 chemistry paper 1 aqa gcse
Mars2501 [29]

Answer:

what do you mean?

Explanation:

7 0
3 years ago
The entropy of an exothermic reaction decreases. This reaction will be spontaneous under which of the following temperatures?
kakasveta [241]

Answer:Low temperatures

Explanation:

∆G= ∆H-T∆S

If ∆H is negative (exothermic reaction), then in order to maintain ∆G<0 which is the condition for spontaneity; T must decrease. This is because, decrease in T will keep the difference of ∆H and T∆S at a negative value in order to satisfy the above stated condition for spontaneity.

3 0
4 years ago
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PLEASE HELP! GIVING 22 POINTS!<br><br> PLEASE GIVE 2-3 SENTENCES!
levacccp [35]
1 --> Jaws
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3 years ago
Why might a scientist repeat an experiment if he/she did not make a mistake in the first one? An experiment should be repeated t
makvit [3.9K]

The answer is C. To ensure the results are accurate.

5 0
3 years ago
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What is the correct name and HELPPP!!
balandron [24]

Answer:

Boron Carbonate; B₂(CO₃)₃

Explanation:

For names, carbonide does not exist; that rules out the first option. Carbide refers to just a carbon atom, not carbon and oxygen as in the polyatomic ion carbonate. That rids us of the third option. We are left with boron carbonate with the formula BCO or boron carbonate with the formula B₂(CO₃)₃.

Recall the carbonate polyatomic ion's formula: CO₃²⁻

Thus BCO cannot be the formula.

Option 4 is your answer, Boron Carbonate; B₂(CO₃)₃.

To further check your answer, observe the oxidation states of boron and the polyatomic ion carbonate. Boron can exist in oxidation states of either 2+ or 3+, and carbonate is only 2-; in this formula, boron will exhibit a 3+ state to balance out with carbonate.

2x3+ = 6+; 3x2- = 6-

6+ + 6- = 0; balanced

5 0
3 years ago
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