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2 years ago

Which of the following instrument would you use to see a plant cell?

Chemistry

2 answers:

olya-2409 [2.1K]2 years ago

7 0

B) is use too see plant cells

Gemiola [76]2 years ago

3 0

B . microscope
this is the answer .

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Describe three signs that a chemical reaction has taken place and give an example of each sign

il63 [147K]

Color change, temperature change, bubbling, state change

green to blue, hot to cold, bubbles (lol), and liquid to gas

7 0

3 years ago

A system of ideas that explains many related observations and is supported by a large body of evidence collected through scienti

wlad13 [49]

B. Theory
The hypothesis that stand the test of time (often tested and never rejected) is called theory. A theory is supported by a great dealcof evidence.

6 0

3 years ago

If the distance between two objects is decreased to - of the original

Charra [1.4K]

Answer:

The new force will be \frac{1}{100} of the original force.

Explanation:

In the context of this problem, we're dealing with the law of gravitational attraction. The law states that the gravitational force between two object is directly proportional to the product of their masses and inversely proportional to the square of a distance between them.

That said, let's say that our equation for the initial force is:

$F = G\frac{m_1m_2}{R^2}The problem states that the distance decrease to 1/10 of the original distance, this means:[tex]R_2 = \frac{1}{10}R$

And the force at this distance would be written in terms of the same equation:

$F_2 = G\frac{m_1m_2}{R_2^2}$

Find the ratio between the final and the initial force:

$\frac{F_2}{F} = \frac{G\frac{m_1m_2}{R_2^2}}{G\frac{m_1m_2}{R^2}}$

Substitute the value for the final distance in terms of the initial distance:

$\frac{F_2}{F} = \frac{G\frac{m_1m_2}{(\frac{R}{10})^2}}{G\frac{m_1m_2}{R^2}}$

Simplify:

$\frac{F_2}{F} = \frac{\frac{1}{100R^2}}{\frac{1}{R^2}}=\frac{1}{100}$

This means the new force will be \frac{1}{100} of the original force.

8 0

3 years ago

The reaction described in Part A required 3.40 L of sodium chloride. What is the concentration of this sodium chloride solution

Mumz [18]

Answer:

Part A:

First, convert molarity to moles by multiplying by the volume:

0.293 M AgNO3 = (0.293 moles AgNO3)/1 L x 1.19 L = 0.349 moles AgNO3

5 0

2 years ago

Rhodium-101 has a half life of 3.3 years. What percent of the sample will remain after 6.6 years?

babunello [35]

Answer:

25%

Explanation:

Half life means that 50% of the sample is gone at 3.3 years. This means that an additional 3.3 years (total 6.6 years) will reduce the sample a further 50% from the point at 3.3 years. In numbers, this means 50% of 50% (0.50*0.50), which is 25%.

5 0

3 years ago