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3 years ago

5

If each of these runners travels the indicated number of spaces in the same amount of time, at which numbered spot will all of t

he runners be next to one another?

1 answer:

Goshia [24]3 years ago

4 0

Answer:

nub 5

Step-by-step explanation:

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) Solve the inequality n -7> -4.<br><br><br><br> HELP ASAP DUE IN A COUPLE HOURS

PilotLPTM [1.2K]

Answer:

n>3

Step-by-step explanation:

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3 years ago

How do u subtract (3x+5y-4)_(4×+11)

AleksAgata [21]

Distribute the negative sign to the 4x and 11 making it 3x+5y-4-4x-11 and combine like terms

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3 years ago

A line passes through the point (8,9) and has a slope of 3/4

stepan [7]

Answer: $y=\frac{3}{4}x+3$

Step-by-step explanation:

Slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept. Since we are given slope, we can plug that into m, and use the given point to find the y-intercept.

$y=\frac{3}{4}x+b$ [plug in (8,9)]

$9=\frac{3}{4}(8)+b$ [multiply]

$9=6+b$ [subtract both sides by 6]

$b=3$

Now that we have b, we can complete the equation to $y=\frac{3}{4}x+3$ .

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3 years ago

Consider the following planes. x + y + z = 6, x + 7y + 7z = 6 (a) Find parametric equations for the line of intersection of the

Lelechka [254]

Answer:

a. $x=6,y=-6t,z=6t$

b. $\theta=29.5^{\circ}$

Step-by-step explanation:

We are given that

$x+y+z=6$

$x+7y+7z=6$

a.Substitute z=0

$x+y=6$ ...(1)

$x+7y=6$ ..(2)

Subtract equation (1) from equation (2)

$6y=0$

$y=0$

Substitute y=0 in equation(1)

$x=6$

The point (6,0,0) lie on a line.

$r_0=(x_0,y_0,z_0)=(6,0,0)$

Let $A=$

$B=$

$A\times B=\begin{vmatrix}i&j&k\\1&1&1\\1&7&7\end{vmatrix}$

$A\times B=i(7-7)-j(7-1)+k(7-1)=-6j+6k$

Therefore, the vector $a'=(a,b,c)=$

Line is parallel to vector a' and passing through the point (6,0,0).

The parametric equation is given by

$x=x_0+at,y=y_0+bt,z=z_0+ct$

Using the formula

The parametric equation is given by

$x=6,y=-6t,z=6t$

Angle between two plane

$a_1x+b_1y+c_1z=d_1$

and $a_2x+b_2y+c_2z=d_2$

$cos\theta=\frac{(a_1,b_1,c_1)\cdot (a_2,b_2,c_2)}{\sqrt{a^2_1+b^2_1+c^2_1}\cdot \sqrt{a^2_2+b^2_2+c^2_2}}$

Using the formula

$cos\theta=\frac{(1,1,1)\cdot(1,7,7)}{\sqrt{1+1+1}\times \sqrt{1+7^2+7^2}}$

$cos\theta=\frac{1+7+7}{\sqrt 3\times 3\sqrt{11}}$

$cos\theta=\frac{15}{3\sqrt{33}}}=\frac{5}{\sqrt{33}}$

$\theta=cos^{-1}(0.87)=29.5^{\circ}$

Where $\theta$ in degree.

3 0

3 years ago

I need help with this question I’m struggling with math during quarantine lol

KIM [24]

Answer:

3rd one: $\frac{5\sqrt{6} }{2}$

Step-by-step explanation:

7 0

3 years ago