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4 years ago

A car accelerates from rest to 24m/s in 8s . what is it's average speed?

Physics

1 answer:

Sidana [21]4 years ago

6 0

During a period of accelerating from zero to 24 m/s, the average speed is 12 m/s.

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Give an example of something that is cyclic and non - cyclic

LiRa [457]

a clock .. and i guess a non functioning clock ?

7 0

3 years ago

How did conflict between countries affect trade along the Silk Road?

Eva8 [605]

Answer:

A: It decreased trade because soldiers no longer protected the oases.

I took it on E2020. I hope I've helped. If you need further explanation, please comment below.

6 0

3 years ago

Read 2 more answers

A 1 mW laser beam is incident onto a detector. Determine the fractional fluctuation in number of photons intercepted by the dete

Ugo [173]

Answer:

(a) $625 photons$

(b) $625\times 10^{6}photons$

Explanation:

Given that , the power of the laser beam is,

$P=1 mW\\P=1\times 10^{-3} W$

and time is given is,

$t=1\mu s\\t=10^{-6}s$

Now the energy formula for the laser beam is,

$E=P\times t$

Now,

$E=10^{-3}\times 10^{-6} \\E=10^{-9}J$

(a) The value of energy is given,

$E_{1}=10MeV\\E_{1}=10\times 10^{6}\times 1.6\times 10^{-19}J\\ E_{1}=16\times 10^{-13}J$

Now the no of photons's fraction fluctuation is,

$n=\frac{E}{E_{1} }\\ n=\frac{10^{-9} }{16\times 10^{-13} }\\ E_{1}=625 photons$

Therefore the no of photons is $625 photons$ .

(b)The value of energy is given,

$E_{z}=10eV\\E_{z}=16\times 10^{-19}J$

Now the no of photons's fraction fluctuation is,

$n=\frac{E}{E_{z} }\\ n=\frac{10^{-9} }{16\times 10^{-19} }\\n=625\times 10^{6}photons$

Therefore the no of photons is $625\times 10^{6}photons$ .

5 0

3 years ago

Waves<br> Please need help fast

mixas84 [53]

I believe its the third answer

6 0

2 years ago

Nonconjugated β,γ-unsaturated ketones are in base-catalyzed equilibrium with their conjugated α,β-unsaturated isomers. The mecha

Viefleur [7K]

Answer:

Explanation:

The equilibrium mechanism for the reversible acid is catalyzed by the isomerization of non conjugated Î², Î³- unsaturated ketones, like 3-cyclohexanone to their conjugated Î±, I²- unsaturated isomers.

Oxygen of the Carbonyl group in the ketone is protonated by the acid and this is followed by the abstraction of an Î±- hydrogen from the protonated 3-cyclo hexanone to yield ethanol

2-cyclo hexanone can be obtained by acid catalyzation of 3-cyclohexanone isomers through the formation of it's "enol".

3 0

3 years ago