Answer: A
Explanation:Convection currents in the mantle Mantle convection is the very slow creeping motion of Earth's solid silicate mantle caused by convection currents carrying heat from the interior to the planet's surface. The Earth's surface lithosphere rides atop the asthenosphere and the two form the components of the upper mantle.
Reflection- looking at yourself in a mirror and seeing the moon in the sky
Refraction- putting on your glasses in order to see more clearly and the pencil looks like it’s bent when you stick one end of it in water.
So, the frequency of that light approximately 
<h3>Introduction</h3>
Hi ! Here I will help you to discuss the relationship between frequency and wavelength, with the velocity constant of electromagnetic waves in a vacuum. We all know that regardless of the type of electromagnetic wave, it will have the same velocity as the speed of light (light is part of electromagnetic wave too), which is 300,000 km/s or
m/s. As a result of this constant property, <u>the shorter the wavelength, the greater the value of the electromagnetic wave frequency</u>. This relationship can also be expressed in this equation:

With the following condition :
- c = the constant of the speed of light in a vacuum ≈
m/s
= wavelength (m)- f = electromagnetic wave frequency (Hz)
<h3>Problem Solving</h3>
We know that :
- c = the constant of the speed of light in a vacuum ≈
m/s
= wavelength =
m.
What was asked :
- f = electromagnetic wave frequency = ... Hz
Step by step :






<h3>Conclusion :</h3>
So, the frequency of that light approximately 
<h3>See More :</h3>
<u>here</u><u> </u><u>is</u><u> </u><u>your</u><u> </u><u>answer</u><u> </u><u>hope</u><u> </u><u>it's</u><u> </u><u>helpful</u><u> </u><u>for</u><u> </u><u>you</u><u> </u><u>thankyou</u><u> </u><u>I</u><u> </u>
A particle has centripetal acceleration whenever it's a making a turn of radius R. If the particle is moving at a constant tangential speed v throughout the turn, then the magnitude of centripetal acceleration is
v²/R
If the particle is following a uniformly circular path, then it moves in a circle of radius R and travels a distance equal to its circumference, 2πR. Let T be the time it takes to complete one such loop. Then the entire circle is traversed with speed v = 2πR/T, so that the centripetal acceleration is also given by
v²/R = (2πR/T)²/R = 4π²R/T²