Answer:
a. the average kinetic energy of hydrogen atoms is 1.20 × 10^-19J
b. the average kinetic energy of helium atoms is 1.24 × 10^-17J
Explanation:
The computation is shown below;
As we know that
Kinetic energy = 3 ÷ 2 kT
where,
K = Boltzmann constant
And, T = Temperature
a. Now the temperature in kelvin is
T = (5,500 × (°C ÷ K) + 273.15 K)
= 5773.15 K
As
Kinetic energy = 3 ÷ 2 kT
So now 1.38 × 10^-23 J/K for K would be substituted and 5773.15 K for Temperature T
Now Kinetic energy is
= 3 ÷ 2 (1.38 × 10^-23 J/K) ( 5773.15 K)
= 1.20 × 10^-19J
hence, the average kinetic energy of hydrogen atoms is 1.20 × 10^-19J
b. As
Kinetic energy = 3 ÷ 2 kT
now 1.38 × 10^-23 J/K for K would be substituted and 6 × 10^5K for Temperature T
Now Kinetic energy is
= 3 ÷ 2 (1.38 × 10^-23 J/K) (6 × 10^5K )
= 1.24 × 10^-17J
hence, the average kinetic energy of helium atoms is 1.24 × 10^-17J
It is given that that initial volume of gas is 20 cubic inches.
The initial pressure is given as 5 psi.
The final pressure is given as 10 psi
We are asked to calculate the final volume.
Let initial and final volume of gas is denoted as 
Let the initial and final pressure of gas is denoted as 
As per the question the temperature of a gas is constant.
From Boyle's law we know that pressure of a given mass of a gas is inversely proportional to the applied volume at constant temperature.
Hence mathematically




Putting the values of these respective quantities as mentioned above we get-

[ans]
Answer:
N₂ = 503.8 N
Explanation:
given,
mass of bottom block = 37 Kg
mass of middle block = 18 Kg
mass of the top block = 16 Kg
force acting on the top block = 170 N
force on the block at top
N₁ be the normal force from block at middle
now,
N₁ = 170 + m g
N₁ = 170 + 16 x 9.8
now, force on block at middle
N₂ be the normal force exerted by the bottom block
N₂ = N₁ + m₂ g
N₂ = 326.8 + 18 x 9.8
N₂ = 503.8 N
hence, normal force by bottom block is equal to N₂ = 503.8 N
Answer:
the transmission axis of polarizing sheet makes an angle of
with the horizontal
Explanation:
We have given that intensity of light incident on the sheet 
Average intensity of light emerging from a polarizing sheet 
We have to find the angle between transmission axis with the horizontal
Intensity of light polarizing from sheet is equal to 
So 



So the transmission axis of polarizing sheet makes an angle of
with the horizontal
(C). Remember gravity provides an acceleration of 9.81m/s^2, so the y component of velocity initial is zero because it isn’t already falling, and we have the height, so basically we use the kinematic equation vf^2=vi^2+2ad, substitute given values and you get vf^2=2(9.81)(65) which is 1275, when you take the square root you get 35.7m/s for final velocity
(B). Then you use vf=vi+at to get the equation 35.7=(9.81)t, when you divide out you get 3.64s for time t
(A). Finally, since we assume that there is no acceleration or deceleration horizonatally, we just multiply the time taken for it to hit the ground and the initial speed ((3.64)(35.7)) to get 129.96, with significant figures I would round that to 130 metres.
**this is in the order that I felt was easiest to answer**