D because choppy water is already a little bit of wave action and then the wind adds a lot of speed to the waves and height to the waves to meek the best waves. Hope this helped.
Answer:
<u>18000 J</u> is the work can do by the motor.
Explanation:
If an electric motor works for 12 seconds and the power output is 1.5 KW = 1500 Watts we need to find how much work can an electric motor does.
We know that,
“Power” is defined as the “rate” of doing “work”, the “energy” transferred or converted per unit time. Mathematically,
Where, units of power is “Watt”, units of work is “Joule” and time in “seconds”.
Substitute the given values to find work
1500 × 12 = work
Work = 18000 Joules
Therefore, work can done by an electric motor is <u>18000 J</u>.
Answer:
x = 4.85 cm
Explanation:
From work energy theorem when dealing with a spring in compression, we know that total work done is;
W_t = ½kx²
Where;
k is Force constant
x is max compression
Now, we know that this is also equal to the kinetic energy.
K.E = ½mv²
Thus;
½kx² = ½mv²
Making x the subject;
x = √(mv²/k)
We are given;
m = 5 kg
v = 2 m/s
k = 85 N/cm = 8500 N/m
Thus;
x = √(mv²/k)
x = √(5 × 2²/8500)
x = 0.0485 m
x = 4.85 cm
The voltage at the plant is HUGEEEE compared to the one at your house. your house functions at 230V , the plant works at thousands times more voltage