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Pavlova-9 [17]
3 years ago
8

A sample of hydrated calcium sulfate has a mass of 20.88 g. After it is heated, it has a mass of 16.51 g. What is the percentage

by mass of water in the hydrate? Use the formula mc010-1.jpg 4.37% 20.9% 26.5% 43.7%
Physics
2 answers:
STALIN [3.7K]3 years ago
6 0
We know that when you heat up calcium sulfate all the water has evaporated from it. That means that the mass of water that was initially in the sulfate is the difference in mass of the sulfate before and after the heating.
m{_H__20}=20.88-16.51=4.37g
In order to <span>get a percentage by mass we simply divide this number by the initial amount of sulfate:
</span>\%_{H__2}O=\frac{4.37}{20.88}=20.93\%<span>
</span>
nexus9112 [7]3 years ago
6 0
The answer is B) 20.9%
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\large\displaystyle\text{$\begin{gathered}\sf \huge \bf{\underline{Data:}} \end{gathered}$}

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                           \large\displaystyle\text{$\begin{gathered}\sf 12.5 \not{min}*\frac{60 \ s}{1\not{min}}=750 \ s \end{gathered}$}

                   \large\displaystyle\text{$\begin{gathered}\sf \bf{A) \ Calculate \ the \ average \ speed: } \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf 402.33 \ m*8 \ laps = 3218.64 \ m \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf d=3218.64 \ m \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf t=750 \ s \end{gathered}$}

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                  \large\displaystyle\text{$\begin{gathered}\sf \bf{B) \ Calculate \ the \ average \ speed \  in \ m/s} \end{gathered}$}

                          \large\displaystyle\text{$\begin{gathered}\sf V=402.33 \ m \end{gathered}$}  

                          \large\displaystyle\text{$\begin{gathered}\sf t=750 \ s \end{gathered}$}

                          \large\displaystyle\text{$\begin{gathered}\sf V=\frac{D}{T} \ \ \ \ \ V=\frac{402.33 \ m}{750 \ s}   \end{gathered}$}\\\\\\\large\displaystyle\text{$\begin{gathered}\sf V= 0.53 \ m/s \end{gathered}$}

4 0
2 years ago
If a fisherman applies a horizontal force with magnitude 47.0 NN to the box and produces an acceleration of magnitude 3.20 m/s2m
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Answer:

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Explanation:

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F = 47.0 N

Acceleration,

a = 3.20 m/s²

Now,

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or,

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⇒    47.0=m\times 3.20

⇒       m=\frac{47.0}{3.20}

⇒           =14.6875 \ kg

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