Answer: 1.8
Explanation:
You are given
the object distance U = 24.8 cm
Focal length F = 16.0 cm
First find the image distance by using the formula:
1/f = 1/u + 1/v
Where V = image distance
Substitute u and f into the formula
1/16 = 1/24.8 + 1/v
1/ v = 1/16 - 1/24.8
1/v = 0.0625 - 0.04032258
1/v = 0.022177
Reciprocate both sides by dividing both sides by one
V = 45.09 cm
Magnification M is the ratio of image distance to the object distance. That is,
M = V/U
Substitute V and U into the formula
M = 45.09/24.8
M = 1.818
Magnification of the image is therefore equal to 1.8 approximately
The change in the kinetic energy refers to the work done in displacing a body, thus, the change in the kinetic energy of an object refers to the work done on the object.
The correct formula to use is:
W = Initial kinetic energy - Final kinetic energy;
Where, W = change in kinetic energy
Final kinetic energy and initial kinetic energy = 1/2 MV^2
Initial velocity = 15 m/s
Final velocity = 13.5 m/s
Initial mass = 0.650 kg
Final mass = 0.950 kg
W = 1/2 [0.650* (15 *15)] - 1/2 [0.950 * (13.5 * 13.5)]
W = 146.25 - 173.13 = 26.88
Therefore, the change in kinetic energy is 26.88 J.
The negative sign has to be ignored, because change in kinetic energy can not be negative.
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Due to the shape of the lens , parallel rays will be deviated
The displacement is the vector with
magnitude
distance between position at 5 sec and position at 8 sec
and direction
direction from position at 5 sec to position at 8 sec .
The route followed during the time interval is irrelevant.
