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xxMikexx [17]
3 years ago
14

Scientific work is currently underway to determine whether weak oscillating magnetic fields can affect human health. For example

, one study found that drivers of trains had a higher incidence of blood cancer than other railway workers, possibly due to long exposure to mechanical devices in the train engine cab. Consider a magnetic field of magnitude 0.00100 T, oscillating sinusoidally at 61.5 Hz. If the diameter of a red blood cell is 7.20 µm, determine the maximum emf that can be generated around the perimeter of a cell in this field.
Physics
1 answer:
nlexa [21]3 years ago
6 0

Answer:

The maximum emf that can be generated around the perimeter of a cell in this field is 1.5732*10^{-11}V

Explanation:

To solve this problem it is necessary to apply the concepts on maximum electromotive force.

For definition we know that

\epsilon_{max} = NBA\omega

Where,

N= Number of turns of the coil

B = Magnetic field

\omega = Angular velocity

A = Cross-sectional Area

Angular velocity according kinematics equations is:

\omega = 2\pi f

\omega = 2\pi*61.5

\omega =123\pi rad/s

Replacing at the equation our values given we have that

\epsilon_{max} = NBA\omega

\epsilon_{max} = NB(\pi (\frac{d}{2})^2)\omega

\epsilon_{max} = (1)(1*10^{-3})(\pi (\frac{7.2*10^{-6}}{2})^2)(123\pi)

\epsilon_{max} = 1.5732*10^{-11}V

Therefore the maximum emf that can be generated around the perimeter of a cell in this field is 1.5732*10^{-11}V

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Tanzania [10]

Answer:

28,400 N

Explanation:

Let's start by calculating the pressure that acts on the upper surface of the hatch. It is given by the sum of the atmospheric pressure and the pressure due to the columb of water, which is given by Stevin's law:

p_{top} = p_{atm} + \rho g h=1.013\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(21.0 m)=3.071 \cdot 10^5 Pa

On the lower part of the hatch, there is a pressure equal to

p_{bot}=p_{atm}=1.013\cdot 10^5 Pa

So, the net pressure acting on the hatch is

p=p_{top}-p_{bot}=3.071 \cdot 10^5 Pa - 1.013\cdot 10^5 Pa=2.058 \cdot 10^5 Pa

which acts from above.

The area of the hatch is given by:

A=\pi r^2 = \pi (\frac{0.420 m}{2})^2=0.138 m^2

So, the force needed to open the hatch from the inside is equal to the pressure multiplied by the area of the hatch:

F=pA=(2.058\cdot 10^5 Pa)(0.138 m^2)=28,400 N

8 0
3 years ago
How to tell how much work gravity does on something?
Grace [21]
By dropping a ball and seeing how long it takes to hit the ground or throw a ball up and time it as well
4 0
3 years ago
The inner planets are different from the outer planets mainly because they are:.
amm1812

Answer:

The inner planets are closer to the Sun and are smaller and rockier. The outer planets are further away, larger and made up mostly of gas. The inner planets (in order of distance from the sun, closest to furthest) are Mercury, Venus , Earth and Mars.

Explanation:

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If you are six feet tall how far back from a 3 foot mirror do you have to stand in order to see yourself completely?
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A silver wire with resistivity 1.59 × 10-8 Ω-m carries a current density of 4.0 A/mm2, What is the magnitude of the electric fie
Nat2105 [25]

Answer:

Electric field, E = 0.064 V/m

Explanation:

It is given that,

Resistivity of silver wire, \rho=1.59\times 10^{-8}\ \Omega-m

Current density of the wire, J=4\ A/mm^2=4\times 10^6\ A/m^2

We need to find the magnitude of the electric field inside the wire. The relationship between electric field and the current density is given by :

E=J\times \rho

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or

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