1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ivanshal [37]
3 years ago
13

6. The table shows the first five energy levels for mercury. A mercury atom makes a transition that emits a photon with a freque

ncy of 4.91 × 1014 Hz. What was the transition? Use GUESS Method!!
Energy levels of mercury:
n energy level eV
1 -10.38
2 -5.74
3 -5.52
4 -4.95
5 -3.71

Physics
1 answer:
bezimeni [28]3 years ago
7 0
Now,
E= 2.03 eV
Also, 
Ef – Ei = E2 – E5 
= -5.74 eV – (–3.71 eV)
= –2.03 eV.
From the conservation of energy, we know that the atom lost energy when that atom emitted the photon. Thus, the transition was from E5 to E2.

The energy levels for an atom are quantized.

You might be interested in
Which feature of a longitudinal wave corresponds to a trough in a transverse wave?
Rama09 [41]
It’s the crest, the crest is the top part of the wave and the trough is the bottom so they correspond
3 0
2 years ago
Read 2 more answers
A motorcycle that is slowing down uniformly. The motorcycle covers 1 ????m=1000 m in 80 sec⁡. The motorcycle then covers the nex
Lynna [10]

Answer:

Part a)

acceleration = -0.042 m/s/s

Part b)

initial speed = 14.17 m/s

final speed = 5.77 m/s

Explanation:

Part a)

Let the initial velocity of the motorcycle is

v_i = v_o

now at the end of 80 s let the speed is

v_f = v_1

after another 120 s let the speed will be

v_f' = v_2

now we know that

d = \frac{v_i + v_f}{2} (t)

d = \frac{v_o + v_1}{2}(80)

1000 = 40(v_o + v_1)

also we know that

v_1 - v_o = a(80)

also we have

1000 = \frac{v_1 + v_2}{2}(120)

1000 = 60(v_1 + v_2)

now we can say

(v_2 + v_1) - (v_o + v_1) = \frac{50}{3} - \frac{50}{2}

also we know

v_2 - v_o = a(120 + 80)

-8.33 = 200 a

a = -0.042 m/s^2

Part b)

now we have

v_1 + v_o = 25

v_1 - v_o = (-0.042)(80)

v_1 = 10.83 m/s

so the starting velocity of the trip is

v_o = 25 - 10.83 = 14.17 m/s

now speed after t = 200 s is given as

v_2 = v_o + at

v_2 = 14.17 - (0.042)(200)

v_2 = 5.77 m/s

5 0
3 years ago
A uniformly charged, one-dimensional rod of length L has total positive charge Q. Itsleft end is located at x = ????L and its ri
GREYUIT [131]

Answer:

|\vec{F}| = \frac{1}{4\pi\epsilon_0}\frac{qQ}{L}(\ln(L+x_0)-\ln(x_0))

Explanation:

The force on the point charge q exerted by the rod can be found by Coulomb's Law.

\vec{F} = \frac{1}{4\pi\epsilon_0}\frac{q_1q_2}{r^2}\^r

Unfortunately, Coulomb's Law is valid for points charges only, and the rod is not a point charge.

In this case, we have to choose an infinitesimal portion on the rod, which is basically a point, and calculate the force exerted by this point, then integrate this small force (dF) over the entire rod.

We will choose an infinitesimal portion from a distance 'x' from the origin, and the length of this portion will be denoted as 'dx'. The charge of this small portion will be 'dq'.

Applying Coulomb's Law:

d\vec{F} = \frac{1}{4\pi\epsilon_0}\frac{qdq}{x + x_0}(\^x)

The direction of the force on 'q' is to the right, since both charges are positive, and they repel each other.

Now, we have to write 'dq' in term of the known quantities.

\frac{Q}{L} = \frac{dq}{dx}\\dq = \frac{Qdx}{L}

Now, substitute this into 'dF':

d\vec{F} = \frac{1}{4\pi\epsilon_0}\frac{qQdx}{L(x+x_0)}(\^x)

Now we can integrate dF over the rod.

\vec{F} = \int{d\vec{F}} = \frac{1}{4\pi\epsilon_0}\frac{qQ}{L}\int\limits^{L}_0 {\frac{1}{x+x_0}} \, dx = \frac{1}{4\pi\epsilon_0}\frac{qQ}{L}(\ln(L+x_0)-\ln(x_0))(\^x)

4 0
3 years ago
⦁ A car going 50 m/s is brought to rest in a distance of 20.0 m as it strikes a pile of dirt. How large an average force is exer
gtnhenbr [62]

Answer:

the average force exerted by seatbelts on the passenger is 5625 N.

Explanation:

Given;

initial velocity of the car, u = 50 m/s

distance traveled by the car, s = 20 m

final velocity of the after coming to rest, v = 0

mass of the passenger, m = 90 kg

Determine the acceleration of the car as it hit the pile of dirt;

v² = u² + 2as

0 = 50² + (2 x 20)a

0 = 2500 + 40a

40a = -2500

a = -2500/40

a = -62.5 m/s²

The deceleration of the car is 62.5 m/s²

The force exerted on the passenger by the backward action of the car is calculated as follows;

F = ma

F = 90 x 62.5

F = 5625 N

Therefore, the average force exerted by seatbelts on the passenger is 5625 N.

8 0
3 years ago
How far will you travel if you walk for 50 seconds at 8 m/s?
Rom4ik [11]

Answer:

تتتتتتتتتتتتتتتت

Explanation:

7 0
3 years ago
Read 2 more answers
Other questions:
  • Which statement best describe nucleic acids
    12·2 answers
  • ]A nuclear power plant produces huge amount of electricity. However, it dumps radioactive wastes into the sea. This has led to a
    9·2 answers
  • A capacitor stores 7.6 × 10–11 C when the electric potential difference between the plates is 5.8 V. What is the electric potent
    8·1 answer
  • A vertical spring with stiffness k originally is at rest with no mass attached. Then, a mass M is attached, and the spring rocks
    11·1 answer
  • A 40.0-$kg$ body is moving in the direction of the positive x axis with a speed of 238 $m/s$ when, owing to an internal explosio
    10·1 answer
  • The grid in a triode is kept negatively charged to prevent...
    15·2 answers
  • What is the kinetic energy of a 24-kg mass that is moving with a velocity of 2 m/s?
    8·2 answers
  • WILL MARK BRAINLIEST!!!!!<br> How is the 3rd law different from the 1st and 2nd laws?
    15·1 answer
  • A What quantity is equal to​
    13·1 answer
  • If a source of waves produces 30 waves per second, what is the frequency in hertz?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!