I’m pretty sure it’s 1. 8:1
Cost per meter(C) = $60/m
Length of rectangular field(L) = 50m
L = 2W
-> W = L/2
-> W = 50/2
-> Width of rectangular field = 25m
Cost of one field length(l) = L x C
-> l = 50 x 60
-> l = $3000
Two of the lengths of the field = 2 x l
-> 2 x $3000
-> $6000
Cost of one field width(w) = W x C
-> w = 25 x 60
-> w = $1500
Two of the widths of the field = 2 x w
-> 2 x $1500
-> $3000
Cost of fencing entire field = $6000+$3000
Hence, total field cost = $9000
PART A:
The generic equation of the line is:
y-yo = m (x-xo)
First we look for the slope of the line:
m = (y2-y1) / (x2-x1)
m = ((5000) - (6000)) / (4-3)
m = -1000
Then, we substitute any point in the generic equation:
(xo, yo) = (4, 5000)
Substituting:
y-5000 = (- 1000) (x-4)
Rewriting:
y = -1000x + 4000 + 5000
y = -1000x + 9000
The equation is:
y = -1000x + 9000
PART B:
For the price of 3.50 we have:
y = -1000 * (3.5) +9000
y = 5500
