3x - 2y = 8 +
===》 46x = 16
43x + 2y = 8
x = 16/46
x = 8/23
______________________________
3x - 2y = 8
3(8/23) - 2y = 8
24/23 - 2y = 8
2y = 24/23 - 8
y = 12/23 - 4
y = 12/23 - 92/23
y = - 80/23
g(-2) + g(2) = 22
Step-by-step explanation:
For x = -2, g(x) = x^2 - 3x
or
g(-2) = (-2)^2 - 3(-2) = 4 + 6 = 10
For x = 2, g(x) = 12, therefore
g(-2) + g(2) = 10 + 12 = 22
<span>1/5
This is a matter of elimination. So let's figure out how many of each display there is.
30% of 150 = 0.30 * 150 = 45 displays about electricity.
2/5 * 150 = 0.40 * 150 = 60 displays about renewable energy
1/10 * 150 = 150/10 = 15 displays about gas.
The rest of the displays are about nuclear power. So
150 - 45 - 60 - 15 = 30 displays about nuclear power. Since we want a fraction, we get 30/150
But 30/150 isn't in it's simplest form. The largest number that will evenly divide both 30 and 150 is 30. So divide both the numerator and denominator by 30
(30/30)/(150/30) = 1/5
So 1/5 of the displays are about nuclear power.</span>
A. 
is the secant line on the below circle.
<u>Step-by-step explanation:</u>
The intersection of the circle will result in either Tangent or Secant. Secant is a line intersecting a circle at two different point. This concept explains the relation between the circle and line intersecting it.
From the given diagram,
The 
and 
intersects the circle at the point H and I.
∴ It can also represented that the 
and intersects at a point G.
From the given options is the secant line that intersects the circle twice.
<span>"Solving for variable 'b'.
Move all terms containing b to the left, all other terms to the right.
Add '-2b' to each side of the equation.
4 + b + -2b = -5 + 2b + -2b
Combine like terms: b + -2b = -1b
4 + -1b = -5 + 2b + -2b
Combine like terms: 2b + -2b = 0
4 + -1b = -5 + 0
4 + -1b = -5
Add '-4' to each side of the equation.
4 + -4 + -1b = -5 + -4
Combine like terms: 4 + -4 = 0
0 + -1b = -5 + -4
-1b = -5 + -4
Combine like terms: -5 + -4 = -9
-1b = -9
Divide each side by '-1'.
b = 9
Simplifying
b = 9"- geteasysolution.com</span>
