70% of 60,000,000 is 42,000,000
Answer: 70
Step-by-step explanation: 6300/90=70 Brainliest please?
Answer: 5%
Step-by-step explanation:
Answer:2
Step-by-step explanation:
Answer:
A. The value of the sample proportion is 0.4
B. The standard error of the sample proportion is 0.02619
C. 0.3487 ≤ p ≤ 0.4513
Step-by-step explanation:
The value of the sample proportion p' is calculated as:
![p'=\frac{x}{n} = \frac{140}{350}=0.4](https://tex.z-dn.net/?f=p%27%3D%5Cfrac%7Bx%7D%7Bn%7D%20%3D%20%5Cfrac%7B140%7D%7B350%7D%3D0.4)
Where x is the number of success in the sample or the number of students that use a laptop in class to take notes and n is the size of the sample or 350 students.
On the other hand, the standard error SE of the sample proportion is calculated as:
![SEs=\sqrt{\frac{p'(1-p')}{n}}](https://tex.z-dn.net/?f=SEs%3D%5Csqrt%7B%5Cfrac%7Bp%27%281-p%27%29%7D%7Bn%7D%7D)
so, replacing the values, we get:
![SE=\sqrt{\frac{0.4(1-0.4)}{350}}=0.02619](https://tex.z-dn.net/?f=SE%3D%5Csqrt%7B%5Cfrac%7B0.4%281-0.4%29%7D%7B350%7D%7D%3D0.02619)
Finally, an approximate 95% confidence interval for the true proportion p is calculate as:
![p'-z_{\alpha/2} SEs \leq p\leq p'+z_{\alpha/2} SEs](https://tex.z-dn.net/?f=p%27-z_%7B%5Calpha%2F2%7D%20SEs%20%5Cleq%20p%5Cleq%20p%27%2Bz_%7B%5Calpha%2F2%7D%20SEs)
Where 1-α is equal to 95%, so
is equal to 1.96. Then, replacing the values we get:
![0.4-1.96(0.02619) \leq p\leq 0.4+1.96(0.02619)](https://tex.z-dn.net/?f=0.4-1.96%280.02619%29%20%5Cleq%20p%5Cleq%200.4%2B1.96%280.02619%29%20)
0.4 - 0.0513 ≤ p ≤ 0.4 + 0.0513
0.3487 ≤ p ≤ 0.4513