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borishaifa [10]
3 years ago
8

Based on the weather station systems shown below, what is the most likely location of the low pressure system?

Physics
2 answers:
11111nata11111 [884]3 years ago
3 0
D just east of Station B
mel-nik [20]3 years ago
3 0
Its B just east of station B
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A galaxy with a lot of dark matter would have a high mass-to-light ratio compared to the Sun. True False
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Yes, a galaxy with a lot of dark matter would have a high mass-to-light ratio compared to the Sun.

<h3>Contribution of dark matter in mass to light ratio?</h3>

This largely invisible matter such as dark matter adds to the mass of the galaxy while it has no contribution in its luminosity which increases the mass-to-light ratio. If dark invisible matter is present in a galaxy, its mass-to-light ratio can be as high.

So we can conclude that the statement is true.

Learn more about galaxy here: brainly.com/question/13956361

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Scientists estimate the age of the universe to be (1 point)
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12-15 billion years i think

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A distant planet with a mass of (7.2000x10^26) has a moon with a mass of (5.0000x10^23). The distance between the planet and the
BARSIC [14]

Answer:

Explanation:

This is a simple gravitational force problem using the equation:

F_g=\frac{Gm_1m_2}{r^2} where F is the gravitational force, G is the universal gravitational constant, the m's are the masses of the2 objects, and r is the distance between the centers of the masses. I am going to state G to 3 sig fig's so that is the number of sig fig's we will have in our answer. If we are solving for the gravitational force, we can fill in everything else where it goes. Keep in mind that I am NOT rounding until the very end, even when I show some simplification before the final answer.

Filling in:

F_g=\frac{(6.67*19^{-11})(7.2000*10^{26})(5.0000*10^{23})}{(6.10*10^{11})^2} I'm going to do the math on the top and then on the bottom and divide at the end.

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3 years ago
A space probe is coasting through space at a steady speed of 100p feet per second. the booster rocket fires for 1/2 seconds so t
aleksandr82 [10.1K]

Answer:

Acceleration: 9800 ft/s^2

Explanation:

The acceleration of an object is equal to the rate of change of velocity:

a=\frac{v-u}{t}

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity to change from u to v

For the space probe in this problem, we have:

u = 100 ft/s (initial velocity)

v = 5000 ft/s (final velocity)

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Therefore, the acceleration is

a=\frac{5000-100}{0.5}=9800 ft/s^2

6 0
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