50.00ml*(10^-3L/ml)*(3.91moles/L) = 0.196 mol
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mass = density x volume
Substitute your values in
mass = 2.7 x 21
Solve:
mass = 56.7g
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Answer : The energy produced from the combustion of 5 mole 
is 
Solution : Given,
Released energy = 803 KJ
The balanced combustion reaction is,
As per the question,
1 mole of releases energy = 803 KJ
5 mole of produced energy = 
Therefore, the energy produced from the combustion of 5 mole is
Ignore this its not the anwser 2.7g
Answer:
D) 2 NOCl(g) ⇄ 2 NO(g) + Cl₂(g); Kp = 1.7 × 10⁻²
Explanation:
In order to compare the degree of decomposition of these reactions, we have to compare the equilibrium constant Kp. Kp is equal to the partial pressure of the products raised to their stoichiometric coefficients divided by the partial pressure of the reactants raised to their stoichiometric coefficients. The higher the Kp, the more products and fewer reactants at equilibrium. Among these reactions, D is the one that has the highest Kp, therefore the one experiencing the largest degree of decomposition.
