Answer:
<h2>
<em>nobel</em><em> </em><em>eleme</em><em>nts</em><em> </em><em>(</em><em>gr</em><em>.</em><em> </em><em>1</em><em>8</em><em>)</em></h2><h2>
<em> </em><em> </em><em> </em><em> </em><em>be</em><em>cause</em><em> </em><em>they</em><em> </em><em>are</em><em> </em><em>fully</em><em> </em><em>stable</em><em> </em><em>due</em><em> </em><em>to</em><em> </em><em>octet</em><em> </em><em>complete</em></h2>
<em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em>
Answer:
A
1. density and composition
2. seismic waves
3.mantle
B.
1. lithosphere
2. asthenosphere
3. mantle
4. outer core
5. inner core
C.
box a I think
For your first question, that equation only works if your situation is occurring at a constant temperature. Your original question is such a situation - everything occurs at 298.15 K. Therefore, you can use this value in the equation to calculate work.
For your second question, Charles' Law describes how the volume of gas changes as you heat or cool it, PROVIDED PRESSURE AND MOLES OF GAS REMAIN CONSTANT THE WHOLE TIME. In your original question above, temperature stays constant while volume changes. However, what they don't tell you is that this necessarily requires a change in either pressure or moles of gas. Because the question works with the same sample the of gas the whole time (i.e. moles are constant), it is pressure that is changing (and this change will occur according to Boyle's Law, since temperature and moles are held constant).
Hope that clarifies things!
Answer:
42672 kJ
Explanation:
Chemical reaction:
C₂H₄ + H₂ → C₂H₆ + heat
Now we calculate the number of moles of ethane C₂H₆:
number of moles = mass / molecular weight
number of moles of ethane = 10.1 / 30 = 0.336 kmoles = 336 moles
And determine the heat released:
if 127 kJ are released when 1 mole of C₂H₆ is produced
then X kJ are released when 336 moles of C₂H₆ is produced
X = (127 × 336) / 1 = 42672 kJ