Following are the Balanced Reactions,
Reaction 1:
(NH₄)₂CO₃ → <u>2</u> NH₄⁺ + CO3⁻²
Reaction 2:
PbI₂ → Pb⁺²<span> + <u>2</u> I</span>⁻¹
Reaction 3:
<span>(NH</span>₂<span>)</span>₃<span>PO</span>₄ → <span><u>3</u> NH</span>₄⁺ <span>+ PO</span>₄⁻³
Answer:
There are four natural states of matter: Solids, liquids, gases and plasma. The fifth state is the man-made Bose-Einstein condensates. Solids.
Explanation:
Hope this helps you out!!
Answer:
-800 kJ/mol
Explanation:
To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).
First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:
Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol
moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄
Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:
ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol
Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).
Answer:
numero de oxidacion: 3+2+2-3
Explanation: