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Elden [556K]
3 years ago
14

I need help on either question you can answer. Thank you god bless

Chemistry
1 answer:
Stels [109]3 years ago
7 0
<h3>Further explanation</h3>

1.Atomic Number (Z) = Mass Number (A) - Number of Neutrons

neutrons = mass number-atomic number

Atomic mass Cl-37= 17

Mass number Cl-37=37

Neutrons = 37-17=20

2. Mass atom X = mass isotope 1 . % + mass isotope 2.%...

\tt atomic~mass~X=0.0224\times 88+0.7832\times 90+0.1944\times 91=90.1

3. The energy in one photon can be formulated as

\large{\boxed{\bold{E\:=\:h\:.\:f}}}

f = c / λ, so :

\tt E\approx f\approx \dfrac{1}{\lambda}

Energy is directly proportional to frequency and inversely proportional to the wavelength

So, as the frequency of photon increases, the energy of photon increases

4. Based on answer number 3 :

A. The wavelength becomes longer, and the energy decreases

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Answer:

About one valence electron

Explanation:

Obviously, removing that electron gives us [Ar] (same configuration as K1+), which is a noble gas and has 8 electrons. Valence electrons are generally regarded as being 'the outermost electrons' for a given atom. Therefore, with neutral potassium, there is one valence electron

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4. Consider the following half-reactions: MnO4–(aq) + 8H+(aq) + 5e– → Mn+2(aq) + 4H2O(l) NO3–(aq) + 4H+(aq) + 3e– → NO(g) + 2H2O
jeyben [28]

Explanation:

The chemical reaction given in the question is as follows -

MnO₄⁻ (aq) + 8H⁺ (aq) + 5e⁻ → Mn²⁺ (aq) + 4H₂O (l)

NO₃⁻ (aq) + 4H⁺ (aq) + 3e⁻ → NO (g) + 2H₂O (l)

As we know , the value for reduction potential are -

Mn²⁺ = + 1.51  V

NO₃⁻  =  +0.96 V

From , the data given above , the value of the reduction potential of NO₃⁻ is less than the reduction potential of Mn²⁺ .

Hence ,

NO₃⁻  can not oxidize Mn²⁺ .

5 0
3 years ago
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