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3 years ago

What is a possible cause of a large percentage of error in an experiment where mgo is produced from the combustion of magnesium?

Chemistry

2 answers:

Dmitry [639]3 years ago

5 0

Answer:

Not all the magnesium has completely reacted.

Explanation:

In a laboratory experiment to produce MgO through burning of a Magnesuim ribbon is achieved when all conditions are observed.

Opening the crucible at intervals slows the rate of the burning magnesium.

The magnesium reacts with air to form MgO.

In most experiments, not all the magnesium gets to completely react.

PilotLPTM [1.2K]3 years ago

4 0

A possible cause of a large percentage of error in an experiment where MgO is produced from the combustion of magnesium would be not all of the Mg has completely reacted. <span>

I hope this helps and if you have any further questions, please don’t hesitate to ask again. </span>

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What is the volume of 1.56 kg of a compound whose molar mass is 81.86 g/mole and whose density is 41.2 g/ml?

hjlf

Answer:

v = 37.9 ml

Explanation:

Given data:

Mass of compound = 1.56 kg

Density = 41.2 g/ml

Volume of compound = ?

Solution:

First of all we will convert the mass into g.

1.56 ×1000 = 1560 g

Formula:

D=m/v

D= density

m=mass

V=volume

v = m/d

v = 1560 g / 41.2 g/ml

v = 37.9 ml

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3 years ago

H is a chemical _____ and H2 is a chemical ______

jeyben [28]

I don’t know if I am right but I think it is symbol for the first one and the second one is formula.

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Why does increasing concentration usually increase reaction rate?

Alex Ar [27]

The correct answer is C) There are more particle collision

With more particle collision, more reactions are created.

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How many liters of CO2 gas can be produced at 30.0 °C and 1.50 atm from the reaction of 5.00 mol of C3H8 and an excess of O2 acc

lbvjy [14]

Answer:

249 L

Explanation:

Step 1: Write the balanced equation

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

Step 2: Calculate the moles of CO₂ produced from 5.00 moles of C₃H₈

The molar ratio of C₃H₈ to CO₂ is 1:3. The moles of CO₂ produced are 3/1 × 5.00 mol = 15.0 mol

Step 3: Convert "30.0°C" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 30.0°C + 273.15 = 303.2 K

Step 4: Calculate the volume of carbon dioxide

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T/P

V = 15.0 mol × 0.0821 atm.L/mol.K × 303.2 K/1.50 atm

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3 years ago

Which type of chemical reaction occurs in Ca + Cl2 mc009-1.jpg CaCl2?

gregori [183]

Answer : The correct option is, (a) Synthesis

Explanation :

Synthesis reaction : A chemical reaction where multiple substances or reactants combine to form a single product.

It is represented as,

$X+Y\rightarrow XY$

Combustion reaction : A chemical reaction in which a hydrocarbon react with the oxygen to give product as carbon dioxide and water.

It is represented as,

$CH_4+2O_2\rightarrow CO_2+2H_2O$

Single replacement reaction : A chemical reaction in which the more reactive element replace the less reactive element.

It is represented as,

$A+BC\rightarrow AC+B$

In this reaction, A is more reactive element and B is less reactive element.

Double replacement reaction : It is a type of chemical reaction where a positive cation and a negative anion of two reactants exchange places to form two new products.

It is represented as,

$XY+AB\rightarrow XB+AY$

(X and A are the cations, Y and B are the anions)

The given reaction is, $Ca+Cl_2\rightarrow CaCl_2$

In this reaction, calcium combine with the chloride to form calcium chloride as a product.

Hence, the given type of reaction is a synthesis reaction.

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