The chemical reaction for this is:
2 C2H6 + 7 O2 => 4 CO2 + 6 H2O
Solving for CO2 with each reactant will give:
21.0 g C2H6 x (1 mol C2H6/30.08 g C2H6) x (6 mol H2O/2
mol C2H6) x (18 g H2O/1 mol H2O) = 37.70 g H2O
110 g O2 x (1 mol O2/32.00 g O2) x (6 mol CO2/7 mol O2) x
(18 g H2O/1 mol H2O) = 53.04 g H2O
Since the amount of H2O in C2H6 is lower therefore C2H6
is the limiting reactant and the maximum amount of water is only 38 g H2O (2 significant digits)
ANswer:
38 g water
From the calculation, the concentration of the oxonium ions is 1 * 10^-6 M
<h3>What is concentration?</h3>
The term concentration refers to the amount of substances present in the solution. There are several units that can be used to show the concertation of a substances such as moles/liter, gram per liter, parts per billion, parts per billion, percentage etc.
Now we know that water is composed of the hydrogen and the hydroxide ions and the product of the both is generally known as the ion product of water and have a value of 1 * 10^-14.
If that be the case, we are in order to write the expression;
[H3O+] [OH-] = 1 * 10^-14
[H3O+] = 1 * 10^-14/ [OH-]
[H3O+] = 1 * 10^-14/ 1 x 10^ -8
[H3O+] = 1 * 10^-6 M
Learn more about concentration:brainly.com/question/10725862
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First, we write the half equations for the reduction of the chemical species present:
Cu⁺² + 2e → Cu; E° = 0.34 V
Ni⁺² + 2e → Ni; E° = - 0.23 V
In order to determine the potential of the cell, we find the difference between the two values. For this:
E(cell) = 0.34 - (-0.23)
E(cell) = 0.57 V
The second option is correct. (The difference in values is due to different values in literature, and it is negligible)
Answer:Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2(g)
O2Zn(s) + H2SO4(aq) → 22nH(aq) + SO4(s)
Explanation:
Answer:
Option d. 7
Explanation:
A mixture of a strong base and a strong acid produce a neutral salt and water.
This is the reaction of neutralization:
HCl + NaOH → NaCl + H₂O
NaCl → Na⁺ + Cl⁻
Sodium chloride is neutral salt which does not give H⁻ neither OH⁻ to medium, that's why pH is neutral.
Both ions are derivated from a strong acid and base so they do not make hydrolisis. They are a conjugate pair of a weak acid and base. The reactions can not occur:
Cl⁻ + H₂O ← OH⁻ + HCl
Na⁺ + H₃O⁺ ← NaOH + H₂O
