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3 years ago

Explain how you can use inverse operations to find 1.8÷3

Mathematics

2 answers:

Aleks04 [339]3 years ago

8 0

1.8 divided by 3 = 5.4

Veronika [31]3 years ago

6 0

To use inverse operations in this problem is by multiplying 1.8 x 3.0 and that gives you 5.4 so your answer is 5.4

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The data are the number of machines in a gym. You sample five gyms. One gym has 12 machines, one gym has 15 machines, one gym ha

Verizon [17]

Answer:

Quantitative discrete data.

Step-by-step explanation:

We have been given a data for the number of machines in five gyms. One gym has 12 machines, one gym has 15 machines, one gym has ten machines, one gym has 22 machines, and the other gym has 20 machines. We are asked to determine the type of the data.

We can see that our given data represents quantity of machines, so our data will be a quantitative data.

Since each gym has a specific number of machines, so our data is discrete and it is not continuous.

Therefore, our given data is a quantitative discrete data.

5 0

3 years ago

Divide 270 in the ratio 3:2:1

Contact [7]

3 + 2 + 1 = 6

270 ÷ 6 = 45

45 × 3 = 135

45 × 2 = 90

45 × 1 = 45

3 : 2 : 1

135 : 90 : 45

6 0

3 years ago

Which value must be added to the expression x2 – 3x to make it a perfect-square trinomial?

Vitek1552 [10]

Answer:

$\frac{9}{4}$

Step-by-step explanation:

Given

x² - 3x

To make the expression a perfect square

add ( half the coefficient of the x- term )²

x² + 2( - $\frac{3}{2}$ )x + $\frac{9}{4}$ , thus

x² - 3x + $\frac{9}{4}$

= (x - $\frac{3}{2}$ )² ← a perfect square

7 0

3 years ago

1) Lithium isotope rations are important to medicine, the 6Li/7Li ratio in a standard reference material was measured several ti

uysha [10]

Answer:

1) $0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588$

$0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219$

b) $ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653$

And we want 2/3 of the margin of error so then would be: $2/3 ME = 0.00001111$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

Replacing we got:

$n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12$

So the answer for this case would be n=12 rounded up to the nearest integer

Step-by-step explanation:

Information given

0.082601, 0.082621, 0.082589, 0.082617, 0.082598

We can calculate the sample mean and deviation with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=0.0826052$ represent the sample mean

$\mu$ population mean

s=0.000013424 represent the sample standard deviation

n=5 represent the sample size

Part 1

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom, given by:

$df=n-1=5-1=4$

The Confidence level is 0.95 or 95%, and the significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ , the critical value would be using the t distribution with 4 degrees of freedom: $t_{\alpha/2}=2.776$