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Ray Of Light [21]
4 years ago
12

How do electrons differ from protons and neutrons?

Chemistry
1 answer:
madam [21]4 years ago
7 0
C?

Electrons are found orbiting around the nucleus of an atom in defined energy levels.
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A compound made of elements A and B, has a cubic unit cell. There is an A atom at each corner of the cube and an A atom at the c
Lorico [155]

Answer:

A₅B₄

Explanation:

Since we have one atom of element A at the center of each face of the unit cell, since the unit cell is a cubic cell, we have 6 faces. Since the atom on the face of the unit cell is shared with another cell, we have half of it in the unit cell is shared So, the number of atoms per face is 1/2 atom/face × 6 faces = 4 atoms on the faces of the unit cell.

Also, we have 1 atom at each corner of the cubic unit cell. Since there are 8 corner in the cubic unit cell. Also, each atom at the corner is shared with 8 unit cells, so we have 1/8 atom per corner. So, the number of atoms per unit cell is 1/8 atom/corner × 8 corners = 1 atoms at the corners of the unit cell.

So, in total we have 4 + 1 = 5 atoms of element A in the unit cell.

Also, there are 4 atoms of element B in the unit cell.

So, the ratio of atoms of element A to element B is 5 : 4.

A:B = 5:4

So, the empirical formula of the compound containing elements A and B is A₅B₄

5 0
3 years ago
What is the maximum most that can be extracted from 76 g og Cr2O3.
tiny-mole [99]

Answer:

D) 152 g

Explanation:

a mass of 1 mol Cr2O3 = 2 × 52 + 3 × 16 = 152 g number of moles of Cr2O3.

7 0
3 years ago
Jamie completes the following steps in an experiment to investigate how temperature affects how fast something will rust in wate
earnstyle [38]

Answer:

I think B

Explanation:

5 0
3 years ago
Read 2 more answers
(will mark brainliest if ou give me the right answer!!!!)
amid [387]

Answer:

D

Explanation:

BEcause you are testing which objects will stick. Your control variable will be the sweater. And the number of times you rub the object on the sweter will not make it stick. It will make it stick for a longer period.

8 0
3 years ago
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Given the lattice energy of NaBr = 736 kJ/mol, the ionization energy of Na = 496 kJ/mol and the electron affinity of Br = −325 k
mars1129 [50]

Answer : The value of \Delta H^o for the reaction is, -565 kJ/mol

Explanation :  

The formation of sodium bromide is,

Na(g)+Br(g)\overset{\Delta H^o}\rightarrow NaBr(s)

\Delta H^o = enthalpy of the reaction

The steps involved in the reaction are:

(1) Conversion of gaseous sodium atoms into gaseous sodium ions.

Na(g)\overset{\Delta H_I}\rightarrow Na^{+1}(g)

\Delta H_I = ionization energy of sodium = 496 kJ/mol

(2) Conversion of gaseous bromine atoms into gaseous bromine ions.

Br(g)\overset{\Delta H_E}\rightarrow Br^-(g)

\Delta H_E = electron affinity energy of bromine = -325 kJ/mol

(3) Conversion of gaseous cations and gaseous anion into solid sodium bromide.

Na^+(g)+Br^-(g)\overset{\Delta H_L}\rightarrow NaBr(s)

\Delta H_L = lattice energy of sodium bromide = -736 kJ/mol

To calculate the \Delta H^o for the reaction, the equation used will be:

\Delta H^o=\Delta H_I+\Delta H_E+\Delta H_L

Now put all the given values in this equation, we get:

\Delta H^o=496kJ/mole+(-325kJ/mole)+(-736kJ/mole)

\Delta H^o=-565kJ/mole

Therefore, the value of \Delta H^o for the reaction is, -565 kJ/mol

7 0
3 years ago
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