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Blizzard [7]
3 years ago
13

What are the common parts of a nucleotide?

Chemistry
1 answer:
a_sh-v [17]3 years ago
8 0
1. Phosphate Group,Pentose sugar, and Nitrogen base
2. Not sure
3.These are found in RNA cytosine, guanine, adenine and uracil.
You might be interested in
you are given 500 mL of a 5M stock solution of ammonium chloride but for your experiment, you only need 100 mL of a 0.65M soluti
mafiozo [28]

Answer:

13ml

Explanation:

  1. to prepare dis solution first you need a volumetric flask of 100ml calibrated .
  2. using dilution formulae u will need 13ml from the stock
  3. measure 13ml of the 5M stock of the 500ml
  4. then drop it into the 100ml calibrated flask
  5. then add water till it reach d mark and you shake thoroughly
6 0
3 years ago
Calculate the number of grams in sodium in 7.6g of Na2C6H6O7 (sodium hydrogen citrate) express your answer using two significant
Katen [24]

Answer:

Explanation:

the molecular mass of Na2C6H6O7 =236 g\mole it has a sodium that has 23 g/mole so 7.6 g of Na2C6H6O7 has x of sodium mass

  236 g/mole ⇒  23g/mole

<h2>   7.6 g  ⇒    ˣ    </h2>

7.6 x 23 ÷ 236  = 74.07×10-2 grams of sodium

<h2 />
7 0
3 years ago
Under standard-state conditions, which of the following species is the best reducing agent? a. Ag+ b. Pb c. H2 d. Ag e. Mg2+
eimsori [14]

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

Reducing agents are defined as the agents which help the other substance to get reduced and itself gets oxidized. They undergo oxidation reaction.

X\rightarrow X^{n+}+ne^-

For determination of reducing agents, we will look at the oxidation potentials of the substance. Oxidation potentials can be determined by reversing the standard reduction potentials.

For the given options:

  • <u>Option a:</u>  Ag^+

This ion cannot be further oxidized because +1 is the most stable oxidation state of silver.

  • <u>Option b:</u>  Pb

This metal can easily get oxidized to Pb^{2+} ion and the standard oxidation potential for this is 0.13 V

Pb\rightarrow Pb^{2+}+2e^-;E^o_{(Pb/Pb^{2+})}=+0.13V

  • <u>Option c:</u>  H_2

This metal can easily get oxidized to H^{+} ion and the standard oxidation potential for this is 0.0 V

H_2\rightarrow 2H^++2e^-;E^o_{(H_2/H^{+})}=0.0V

  • <u>Option d:</u>  Ag

This metal can easily get oxidized to Ag^{+} ion and the standard oxidation potential for this is -0.80 V

Ag\rightarrow Ag^{+}+e^-;E^o_{(Ag/Ag^{+})}=-0.80V

  • <u>Option e:</u>  Mg^{2+}

This ion cannot be further oxidized because +2 is the most stable oxidation state of magnesium.

By looking at the standard oxidation potential of the substances, the substance having highest positive E^o potential will always get oxidized and will undergo oxidation reaction. Thus, considered as strong reducing agent.

From the above values, the correct answer is Option b.

8 0
3 years ago
Convert from moles to particles 6.02x1023 particles 1 mole Question 2. 2.7 moles of lithium Question 3. 1.8 moles of sodium chlo
spayn [35]

Considering the definition of Avogadro's number:

  • the number of molecules of lithium is 1.62621×10²⁴ molecules.
  • the number of molecules of sodium chloride is 1.08414×10²⁴ molecules.

<h3>Definition of Avogadro's number</h3>

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>Amount of molecules in this case</h3>

You can apply the following rule of three, considering the Avogadro's number:  If 1 mole of lithium contains 6.023×10²³ molecules, 2.7 moles of lithium contains how many molecules?

amount of molecules of lithium= (6.023×10²³ molecules × 2.7 moles)÷1 mole

<u><em>amount of molecules of lithium=1.62621×10²⁴ molecules</em></u>

Finally, the number of molecules of lithium is 1.62621×10²⁴ molecules.

On the other hand you can apply the following rule of three, considering the Avogadro's number:  If 1 mole of sodium chloride​ contains 6.023×10²³ molecules, 1.8 moles of  sodium chloride​ contains how many molecules?

amount of molecules of sodium chloride= (6.023×10²³ molecules × 1.8 moles)÷1 mole

<u><em>amount of molecules of sodium chloride=1.08414 ×10²⁴ molecules</em></u>

Finally, the number of molecules of sodium chloride is 1.08414×10²⁴ molecules.

Learn more about Avogadro's Number:

brainly.com/question/11907018

brainly.com/question/1445383

brainly.com/question/1528951

#SPJ1

4 0
2 years ago
What is the volume of 1.60 grams of O2 gas at STP? (5 points)
tiny-mole [99]

Answer:

  • <u><em>1.12 liters</em></u>

Explanation:

<u>Calculating number of moles</u>

  • Molar mass of O₂ = 32 g
  • n = Given weight / Molar mass
  • n = 1.6/32
  • n = 0.05 moles

<u>At STP</u>

  • One mole of O₂ occupies 22.4 L
  • Therefore, 0.05 moles will occupy :
  • 22.4 L x 0.05 = <u><em>1.12 L</em></u>
5 0
2 years ago
Read 2 more answers
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