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2 years ago

Why is pure silicon a poor conductor at room temperature?

1 answer:

Alex2 years ago

6 0

The appropriate answer is a. it's valence electrons are held tightly within the crystal structure. Metals are good conductors because they share electrons and so they are free to move about enabling it to be a good conductor. Any substance that has electrons tightly held within bonds will not be good conductors. If the structure of pure silicon had its valence electrons held loosely by a positive nucleus then it would be able to conduct.

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Ben has a snack with a combination of raisins, chocolate pieces, and nuts. As he eats the snack, Ben picks out all of the raisin

erastova [34]

Answer:

Trail Mix

Explanation:

The best description for the snack that Ben is eating would be Trail Mix. This is a very common snack for hikers, hence the name, since it is very healthy and great for taking on hikes since it does not get affected by the sun. This snack was originally called GORP which stands for "good old raisins and peanuts" because the snack originally contained only raisins and peanuts. It has since changed to include various different ingredients such as a variety of nuts, chocolate pieces, dried fruit, cereal etc.

7 0

2 years ago

A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu

OLEGan [10]

Answer: The final temperature of nickel and water is $25.2^{o}C$ .

Explanation:

The given data is as follows.

Mass of water, m = 55.0 g,

Initial temp, $(t_{i}) = 23^{o}C$ ,

Final temp, $(t_{f})$ = ?,

Specific heat of water = 4.184 $J/g^{o}C$ ,

Now, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$

Also,

mass of Ni, m = 15.0 g,

Initial temperature, $t_{i} = 100^{o}C$ ,

Final temperature, $t_{f}$ = ?

Specific heat of nickel = 0.444 $J/g^{o}C$

Hence, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

$q_{water}(gain) = -q_{alloy}(lost)$

$55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$ = -( $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$ )

$t_{f} = \frac{25.9^{o}C}{1.029}$

= $25.2^{o}C$

Thus, we can conclude that the final temperature of nickel and water is $25.2^{o}C$ .

6 0

2 years ago

Erika is asked to create a model showing a negatively charged Carbon ion. Which model should she create?

OverLord2011 [107]

I am pretty sure u have pictures and this one should be the one that erika should make

8 0

2 years ago

One mole of copper(ii) sulfate, cuso4, contains ________ o atoms.

Ierofanga [76]

According to avogadro constant, the number of units in one mole of any substance contain 6.022 x10 ^23 atoms

therefore the number of o atoms in one mole of CuSO4 = 6.022 x 10 ^ 23

6 0

2 years ago

Read 2 more answers

A nuclide of phosphorus 3015P decays into a nuclide of silicon 3014Si. In order to satisfy charge conservation and lepton number

jeka94

In order to satisfy charge conservation and lepton number conservation the other products must be neutron.

<h3>What is conservation of mass?</h3>

The principle of conservation of mass states that, the sum of the initial mass of reactants must be equal to final mass of the products.

$_{15}^{30}P\ --- > \ _{14}^{30} Si \ + \ ^{0}_{1} n$

The balanced reaction of radioactive decay of phosphorous shows conservation of mass.

Thus, in order to satisfy charge conservation and lepton number conservation the other products must be neutron.

Learn more about radioactive decay here: brainly.com/question/1383030

#SPJ1

3 0

1 year ago