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expeople1 [14]
3 years ago
14

How many atoms of Cl are there in 25 moles of Cl(subscript)2 ? Can someone show the work and explain this to me I'm so lost

Chemistry
1 answer:
Verizon [17]3 years ago
5 0
One mole of a substance contains 6.022×10^23 atoms

25mols of Cl2 actually contains 50moles of Cl because it is a diatomic molecule
so the answer is 50 ×6.022×10^23 = 3.011×10^25 atoms of Chlorine
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How many lone pairs does CO2 have? Does it have Single bonds or Double bonds? Does it obey the octet rule?
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The molecule CO2 have 2 lone pairs located in the oxygen atoms. It has two double bonds also connecting carbon atom to the two oxygen atoms. It does obey the octet rule so the atoms need 8 electrons in each of them that is why electrons are shared.
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How is the periodic table organized?
joja [24]

Answer:

The periodic table of elements arranges all of the known chemical elements in an informative array. Elements are arranged from left to right and top to bottom in order of increasing atomic number. Order generally coincides with increasing atomic mass. The rows are called periods.

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8 0
3 years ago
Read 2 more answers
Heating 235 g of water from 22.6°C to 94.4°C in a microwave oven requires 7.06 × 104 J of energy. If the microwave frequency is
Darya [45]

Answer: 3.69 × 10^27

Explanation:

Amount of energy required = 7.06 × 10^4 J

Frequency of microwave (f) = 2.88 × 10^10 s−1

Planck's constant (h) = 6.63 × 10^-34 Jᐧs/quantum

Recall ;

Energy of photon = hf

Therefore, energy of photon :

(6.63 × 10^-34)j.s× (2.88 × 10^10)s^-1

= 19.0944 × 10^(-34 + 10) = 19.0944×10^-24 J

Hence, number of quanta required :

(7.06 × 10^4)J / (19.0944 × 10^-24)J

= 0.369 × 10^(4 + 24) = 0.369×10^28

= 3.69 × 10^27

6 0
3 years ago
PLEASE HELP ASAP WILL GIVE BRAINLIEST
kirill115 [55]

The amount of heat required to convert H₂O to steam is :  382.62 kJ

<u>Given data :</u>

Mass of liquid water  ( m ) = 150 g

Temperature of liquid water = 43.5°C

Temperature of steam = 130°C

<h3 /><h3>Determine the amount of heat required </h3>

The amount of heat required = ∑ q1 + q2 + q3 ----- ( 1 )

where ;

q1 = heat required to change Temperature of water from 43.5°C to 100°C .  q2 = heat required to change liquid water at 100°C to steam at 100°C

q3 = heat required to change temperature of steam at 100°C to 130°C

  • For q1

M* S_{water}*ΔT

= 150 * 4.18 * ( 100 - 43.5 )

= 35425.5 J

  • For q2

moles * ΔHvap

= (150 / 18 )* 40.67 * 1000

=  338916.67 J

  • For q3

M * S_{steam} * ΔT

= 150 * 1.84 * ( 130 -100 )

= 8280 J

Back to equation ( 1 )

Amount of heat required = 35425.5  + 338916.67 + 8280 = 382622.17 J

                                                                                               ≈ 382.62 kJ

Hence we can conclude that The amount of heat required to convert H₂O to steam is :  382.62 kJ.

Learn more about Specific heat of water : brainly.com/question/16559442

6 0
3 years ago
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