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expeople1 [14]
3 years ago
14

How many atoms of Cl are there in 25 moles of Cl(subscript)2 ? Can someone show the work and explain this to me I'm so lost

Chemistry
1 answer:
Verizon [17]3 years ago
5 0
One mole of a substance contains 6.022×10^23 atoms

25mols of Cl2 actually contains 50moles of Cl because it is a diatomic molecule
so the answer is 50 ×6.022×10^23 = 3.011×10^25 atoms of Chlorine
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A strong acid, HA, is added to water. Which statement about the solution is true?
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My answer to this question is C

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Isotopes

Explanation:

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2. Mitosis is great for repair and damage. TRUE OR FALSE
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Calculate the concentration of A bottle of wine contains 12.9% ethanol by volume. The density of ethanol (CH3OH) is 0.789 g/cm e
Delicious77 [7]

Answer:

The mass percentage of the solution is 10.46%.

The molality of the solution is 2.5403 mol/kg.

Explanation:

A bottle of wine contains 12.9% ethanol by volume.

This means that in 100 mL of solution 12.9  L of alcohol is present.

Volume of alcohol = v = 12.9 L

Mass of the ethanol = m

Density of the ethanol ,d= 0.789 g/cm^3=0.789 g/mL

1 cm^3=1 mL

m=d\times v=0.798 g/ml\times 12.9 mL = 10.1781 g

Mass of water = M

Volume of water ,V= 100 mL - 12.9 mL = 87.1 mL

Density of water = D=1.00 g/mL

M=D\times V=1.00 g/ml\times 87.1 mL =87.1 g

Mass percent

(w/w)\%=\frac{m}{m+M}\times 100

\frac{10.1781 g}{10.1781 g+87.1 g}\times 100=10.46\%

Molality :

m=\frac{m}{\text{molar mass of ethanol}\times M(kg)}

M = 87.1 g = 0.0871 kg (1 kg =1000 g)

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4 0
3 years ago
A 100.0 mL sample of 0.10 M NH3 is titrated with 0.10 M HNO3. Determine the pH of the solution before the addition of any HNO3.
alex41 [277]

Answer:

pH=11.12

Explanation:

Hello,

In this case, ammonia dissociation is:

NH_3(aq)+H_2O(l)\rightleftharpoons NH_4^+(aq)+OH^-(aq)

So the equilibrium expression:

Kb=\frac{[NH_4^+][OH^-]}{[NH_3]}

That in terms of the reaction extent and the initial concentration of ammonia is written as:

1.8x10^{-5}=\frac{x*x}{0.10M-x}

Thus, solving by using solver or quadratic equation we find:

x=0.00133M

Which actually equals the concentration of hydroxyl ion, therefore the pOH is computed:

pOH=-log([OH^-])=-log(0.00133)=2.88

And the pH from the pOH is:

pH=14-pOH=14-2.88\\\\pH=11.12

Best regards.

6 0
3 years ago
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