Answer:
4FeS + 7O₂ ----> 2Fe₂O₃ + 4SO₂
Explanation:
You have to drag the elements shown on the right under the formula. For example, you would have to drag 4 of the FeS molecules under the 4FeS text in the formula. Then place 7 O₂ molecules under the 7O₂ text, etc.
Since hydrogen bonding is a stronger intermolecular force than van der Waals forces, more energy is required to separate the molecules of ethanol than the molecules of ethane. Thus ethanol has a higher melting point than ethane.
it was earnest rutherford he did the gold foil experiment where he shot alpha particles at gold foil that was supposed to be about 1 atom thick. He expected all the atoms to pass straight through but some bounced back, so he proposed that there was something small dense and positive in atoms aka the nucleus
Answer: 3.42 moles CO = 84.0g, is not true.
Explanation:
Moles is given by the formular; Mass / Molar Mass.
Therefore; 0.2 moles O2 = 6g is true when we multiply 32g x 0.2 = 6g approximately.
0.75 moles H2CO3 = 47g.
Molar formular for H2CO3 = 2 + 12 + 48 =62g.
If we multiply 62g (molar mass ) by 0.75moles, it gives us 47g approximately.
3.42 moles CO = 84g
molar mass of CO = 12 + 16 = 28g
Multiply 28g x 3.42 moles = 95.76g, which is not true.
Answer:
E = 5×10⁻¹⁹ J
Explanation:
Given data:
Wavelength = 400 nm (400×10⁻⁹ m)
Energy of wave = ?
Solution:
Formula:
E = h c/λ
c = 3×10⁸ m/s
h = 6.63×10⁻³⁴ Js
Now we will put the values in formula.
E = 6.63×10⁻³⁴ Js × 3×10⁸ m/s /400×10⁻⁹ m
E = 19.89×10⁻²⁶ J.m / 400×10⁻⁹ m
E = 0.05×10⁻¹⁷ J
E = 5×10⁻¹⁹ J
