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STALIN [3.7K]
2 years ago
6

Hydrogen gas reacts with oxygen gas to form water. What is the excess reactant in this recation(Refer to the picture below to an

swer).
A. Water
B. Hydrogen gas
C. Oxygen gas
D. Water and oxygen gas

Chemistry
1 answer:
Studentka2010 [4]2 years ago
7 0

Answer: C. Oxygen Gas

Explanation: When Hydrogen Gas and Oxygen Gas combine together it forms water correct. When you have an excess amount of another it stays neutral because it has no other molecule to react with.

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A sound wave from a jackhammer travels through a section of concrete with a fixed frequency. At the concrete's boundary is mud.
Ira Lisetskai [31]

Answer:

It might be too late now, but the correct answer for the question is B.

Explanation:

According to the graph you can see when it hit the boundary of the mud it curved downward making the direction change; which then the mud probably had a hollow shell, where the speed was moving much faster.

6 0
2 years ago
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Energy pyramid worksheet
Taya2010 [7]

Answer:

From top to bottom coyote, crow, squirrel, then acorn

Explanation:

The coyote has the least amount of energy and its the biggest predator so it belongs at the top. The crows eat squirrels and the squirrels eat acorns.

6 0
3 years ago
What is the most abundant gas in the atmosphere is _____. argon oxygen nitrogen hydrogen
Serga [27]
Hey there princesswalkeror4ori,

By far, the most abundant gas in the Earth's atmosphere<span> is </span>nitrogen<span>, which accounts for about 78% of the mass of dry air. </span>Oxygen is<span> the next most abundant gas, present at levels of 20 to 21%. Although humid air seems like it contains a lot of water, the maximum </span>amount of water vapor<span> that air can hold is only about 4%.
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Hope I helped!

Have a great day!

7 0
3 years ago
Read 2 more answers
For the reaction below, Kp = 1.16 at 800.°C. CaCO3(s) equilibrium reaction arrow CaO(s) + CO2(g) If a 25.0-g sample of CaCO3 is
goblinko [34]

Answer:

76.0%

Explanation:

Let's consider the following reaction.

CaCO₃(s) ⇄ CaO(s) + CO₂(g)

At equilibrium, the equilibrium constant Kp is:

Kp = 1.16 = pCO₂ ⇒ pCO₂ = 1.16 atm

We can calculate the moles of CO₂ at equilibrium using the ideal gas equation.

P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{1.16atm\times 14.4 L}{(0.08206atm.L/mol.K)\times 1073K} =0.190mol

From the balanced equation, we know that 1 mole of CO₂ is produced by 1 mole of CaCO₃. Taking into account that the molar mass of CaCO₃ is 100.09 g/mol, the mass of CaCO₃ that reacted is:

0.190molCO_{2}.\frac{1molCaCO_{3}}{1molCO_{2}} .\frac{100.09gCaCO_{3}}{1molCaCO_{3}} =19.0gCaCO_{3}

The percentage by mass of the CaCO₃ that reacted to reach equilibrium is:

\frac{19.0g}{25.0g} \times 100\%=76.0\%

5 0
2 years ago
What is the percentage of s-character in an sp hybrid? O 25% 50% o 75% O 66%
marishachu [46]

Answer: 50%

Explanation:

The number of electron pairs are 2 for hybridization to be sp and the electronic geometry of the molecule will be linear.

1. percentage of s character in sp hybrid orbital =\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{2}\times 100=50\%

2. percentage of s character in sp^2 hybrid orbital =\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{3}\times 100=33.3\%

3. percentage of s character in sp^3 hybrid orbital =\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{4}\times 100=25\%

Thus percentage of s-character in an sp hybrid is 50%.

8 0
2 years ago
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