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monitta
3 years ago
8

I’d like to know how to solve this problem.

Mathematics
1 answer:
sergiy2304 [10]3 years ago
6 0
Can you show the problem? Those are the questions but I need the actual graph.
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45°,35°,x° please answer my question
Bingel [31]
A triangles measure = 180
45 + 35 + x = 180
80 + x = 180
x = 100
Hope this helps!
3 0
3 years ago
An electrician has 4.1 meters of wire.
aleksklad [387]
A)He can cut 5 strips of of 7/10m.

7/10=0.7m

0.7*5=3.5m 
3.5m of wire wil be used in cutting possible 7/10m pieces.

b)Leftover will be 0.6m.
4.1-3.5=0.6m


4 0
3 years ago
Read 2 more answers
Solve this question fast....in the attachment​
avanturin [10]

Answer:

z = 4

y = -1

x = 2

Step-by-step explanation:

x - y = 3

Therefore => x = 3 + y

y + 2z =7

Therefore => y= 7 - 2z

We have the equation :

2x + 3y + 4z = 17

2(3 + y) + 3(7 - 2z) + 4z = 17

6 + 2y + 21 - 6z +4z = 17

2(7 -2z) - 2z + 27 = 17

14 - 4z - 2z + 27 = 17

-6z + 41 = 17

-6z = -24

z = 4

4 0
2 years ago
What is the interest you will pay if you borrowed $120 at 5% interest for 6 years?
kobusy [5.1K]

Answer:

Hope this helps!

Step-by-step explanation:

We will need the loan payment formula:

That formula is really complex and we expect you to solve it.

Your monthly payment would be $1.93 per month for 6 years making the TOTAL loan cost 1.93 * 12 * 6 = 138.96

Since the principal you borrowed is $120 the total interest =

(138.96 minus 120.00) which equals $18.96

6 0
3 years ago
Read 2 more answers
Find the exact length of the curve. 36y2 = (x2 − 4)3, 5 ≤ x ≤ 9, y ≥ 0
IrinaK [193]
We are looking for the length of a curve, also known as the arc length. Before we get to the formula for arc length, it would help if we re-wrote the equation in y = form.

We are given: 36 y^{2} =( x^{2} -4)^3
We divide by 36 and take the root of both sides to obtain: y = \sqrt{ \frac{( x^{2} -4)^3}{36} }

Note that the square root can be written as an exponent of 1/2 and so we can further simplify the above to obtain: y =  \frac{( x^{2} -4)^{3/2}}{6} }=( \frac{1}{6} )(x^{2} -4)^{3/2}}

Let's leave that for the moment and look at the formula for arc length. The formula is L= \int\limits^c_d {ds} where ds is defined differently for equations in rectangular form (which is what we have), polar form or parametric form.

Rectangular form is an equation using x and y where one variable is defined in terms of the other. We have y in terms of x. For this, we define ds as follows: ds= \sqrt{1+( \frac{dy}{dx})^2 } dx

As a note for a function x in terms of y simply switch each dx in the above to dy and vice versa.

As you can see from the formula we need to find dy/dx and square it. Let's do that now.

We can use the chain rule: bring down the 3/2, keep the parenthesis, raise it to the 3/2 - 1 and then take the derivative of what's inside (here x^2-4). More formally, we can let u=x^{2} -4 and then consider the derivative of u^{3/2}du. Either way, we obtain,

\frac{dy}{dx}=( \frac{1}{6})( x^{2} -4)^{1/2}(2x)=( \frac{x}{2})( x^{2} -4)^{1/2}

Looking at the formula for ds you see that dy/dx is squared so let's square the dy/dx we just found.
( \frac{dy}{dx}^2)=( \frac{x^2}{4})( x^{2} -4)= \frac{x^4-4 x^{2} }{4}

This means that in our case:
ds= \sqrt{1+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{4}{4}+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{x^4-4 x^{2}+4 }{4}} dx
ds= \sqrt{\frac{( x^{2} -2)^2 }{4}} dx
ds=  \frac{x^2-2}{2}dx =( \frac{1}{2} x^{2} -1)dx

Recall, the formula for arc length: L= \int\limits^c_d {ds}
Here, the limits of integration are given by 5 and 9 from the initial problem (the values of x over which we are computing the length of the curve). Putting it all together we have:

L= \int\limits^9_5 { \frac{1}{2} x^{2} -1 } \, dx = (\frac{1}{2}) ( \frac{x^3}{3}) -x evaluated from 9 to 5 (I cannot seem to get the notation here but usually it is a straight line with the 9 up top and the 5 on the bottom -- just like the integral with the 9 and 5 but a straight line instead). This means we plug 9 into the expression and from that subtract what we get when we plug 5 into the expression.

That is, [(\frac{1}{2}) ( \frac{9^3}{3}) -9]-([(\frac{1}{2}) ( \frac{5^3}{3}) -5]=( \frac{9^3}{6}-9)-( \frac{5^3}{6}-5})=\frac{290}{3}


8 0
3 years ago
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