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monitta
3 years ago
8

I’d like to know how to solve this problem.

Mathematics
1 answer:
sergiy2304 [10]3 years ago
6 0
Can you show the problem? Those are the questions but I need the actual graph.
You might be interested in
1. Solve: 6x - 12 &lt; 6<br> 2. Solve: 2(3x-8) &gt;8
8090 [49]

Answer:

Step-by-step explanation:

1. here you go mate

step 1

6x - 12 < 6  equation

step 2

6x - 12 < 6  simplify

6x-12+12<6+12

step 3

6x<18  Divide both sides

\frac{6x}{6}

answer

x<3

2. Here you go mate

step 1

2(3x-8) >8  equation

step 2

2(3x-8) >8  simplify

6x-16+16>8+16

step 3

6x>24  divide both sides

\frac{6x}{6} >\frac{24}{6}

answer

x>4

4 0
3 years ago
A class of 33 students elected a class treasurer. There were 11 votes for Candidate A and 15 votes for Candidate B. The remainin
vovangra [49]
To start out, notice that you want the percent of voters that chose candidate A, not the percent of the class that chose candidate A.

Your fraction should be "number that chose candidate A" out of "number of voters," which is the same thing as saying:  
"number that chose candidate A" divided by "number of voters"

1) The numerator of the fraction should be the number of votes for candidate A, which is 11.

2) The denominator of the fraction should be the number of voters. You're told that "t<span>here were 11 votes for Candidate A and 15 votes for Candidate B," so there are:
</span>11 + 15 \: total \: votes

3) Finally put parts 1 and 2 together into a fraction and multiply by 100 to get your percent. That is your final answer:
\frac{11}{11+15}  \times 100

----

Answer: Top right choice, \frac{11}{11+15} \times 100
<span>

</span>
5 0
3 years ago
50b 50=11b 95 what is b?
ohaa [14]
<span>50b 50=11b 95 collect the like terms 
50b-11b=95-50
39b=45 divide both sides by 39
b=1.2</span>
7 0
3 years ago
A rubber ball is dropped onto a hard surface from a height of 9 feet, and it bounces up and down. At each bounce it rises to 80%
8_murik_8 [283]
There are 12 inches in a foot, so 9ft = 108in. Also, 80% = 0.8. Therefore the formula is: h(n) = 108 * 0.8^n. To find the bounce height after 10 bounces, substitute n=10 into the equation: h(n) = 108 * 0.8^10 = 11.60in (2.d.p.). Finally to find how many bounces happen before the height is less than one inch, substitute h(n) = 1, then rearrage with logarithms to solve for the power, x: 108 * 0.8^x = 1; 0.8^x = 1/108; Ln(0.8^x) = ln(1/108); xln(0.8) = ln(1\108); x = ln(1/108) / ln(0.8) = -4.682 / -0.223 = 21 bounces
4 0
3 years ago
What's the answer to this question
jasenka [17]
Tan w=20/83
inverse tan 20/83=13.55 degrees
3 0
3 years ago
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