Answer:
y^2
Step-by-step explanation:
2y^3 + y^2 and 4y^4 + 2y^3
2y^3 + y^2......factor out y^2
y^2(2y + 1)
4y^4 + 2y^3...factor out y^2
y^2(4y^2 + 2y)
I would normally factor out 2y^3 out of this one...but u cant do it in the other one...the only common factor is gonna be y^2
the common factor is y^2 <===
10 times 4 equals 40 and 1 times 40 equals 40
35x – 13 x = x – 1
⇒ 22 x = x - 1
⇒ 22x - x = -1
⇒ 21x = -1
⇒ x = -1/21
Thus,the value of x is -1/21
Answer:
4 ( 4 + 4 + 4 )
Step-by-step explanation:
There are 13 entries in total
The owner has 5 horses.
If each horses has the same probability of winning, then the probability that the owners
Horses will come in first, second, third, and fourth will be as follows:
It was only specified that one of these horses needed to be in each position
This makes it is a combination type problem because order does not matter
We 5 horses
The probability that one of those 5 horses will be first is 5/13
The probability that one of those remaining 4 horses will be second is 4/12
The probability that one of those remaining 3 horses will be third is 3/11
The probability that one of those remaining 2 horses will be fourth is 2/10
The probability that one of those remaining 1 horses will be fifth is 5/9
The total probability is that 0.00389