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blsea [12.9K]
3 years ago
8

Plz answer asap thanks

Mathematics
2 answers:
tester [92]3 years ago
8 0
The answer is 44%.!!!!!!!!!!!!!!!!!!!!!!!!!!!
Elanso [62]3 years ago
3 0
44% because to get to a 100% you have to subtract the 100 and 56 which would be 44%
Hope it helps:)














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Toby goes on holiday to Geneva, Switzerland. In Geneva, Toby sees a watch costing 193.75 CHF (Swiss Francs). In Manchester, an i
KonstantinChe [14]

Answer:

The watch is cheaper in Geneva, Switzerland by a value of £20

Step-by-step explanation:

To get the city in which the watch is cheaper, what we need to do is to express the price of the watch in the same currency.

Since pounds is also used in the b part of the question, it would be easier working with it.

In Geneva, the price of the watch is 193.75 CHF

from our conversion formula;

£1 = 1.55 CHF

£x = 193.75 CHF

We cross multiply to get the value of x

(193.75 * 1)/1.55

= 193.75/1.55 = £125

We can see that the watch costs less in Geneva and higher in Manchester

By how much is it cheaper?

We can calculate this by subtracting the value in Geneva from the value in Manchester

That would be 145-125 = £20 cheaper

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Answer:

The answer in the attached figure

Step-by-step explanation:

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f(x)=0.2^{x} +3

Using a graphing tool

see the attached figure

The answer in the attached figure

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Lynna [10]
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Name 4 equivalent fractions that equall to 0.7
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If PQRS is a rhombus, which statements must be true? Check all that apply.
bezimeni [28]
These statements are true:

\bold{First.} \ \overline{PS} \ is \ parallel \ to \ \overline{QR}

This is <em>true</em> because of the definition of a rhombus which states that opposite sides are parallel.

Then \ \overline{PS} \ is \ opposite \ to \ \overline{QR}

\bold{Second.} \ \overline{PR} \ is \ perpendicular \ to \ \overline{QS}

This is <em>true </em>because the diagonals of a rhombus bisect each other at right angles.

\bold{Third.} \ \overline{PQ}=\overline{RS}

This is<em> true</em> because the four sides of a rhombus are all equals.

\bold{Fourth.} \ \angle PQR \ is \ supplementary \ to \ \angle QPS

This is also <em>true</em>. Two angles are supplementary when they add up to 180 degrees. Angles in rhombus are equal two to two. Let's name:

\angle PQR = \alpha \ and \ \angle QPS = \beta 

Then it is true that:

\angle PQR=\angle PSR \ and \ \angle QPS=\angle QRS

Besides, a rhombus is a quadrilateral and it is true that the interior angles of a quadrilateral add up to 360 degrees, thus:

2\alpha+2\beta=360 \\ \\ \therefore \boxed{\alpha+\beta = 180^\circ}

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